{"id":422,"date":"2025-07-22T01:54:00","date_gmt":"2025-07-22T01:54:00","guid":{"rendered":"https:\/\/giapsgk.com\/chuyen-de\/?p=422"},"modified":"2025-07-22T02:47:07","modified_gmt":"2025-07-22T02:47:07","slug":"tong-hop-cong-thuc-toan-10-canh-dieu-hoc-ki-1-va-hoc-ki-2","status":"publish","type":"post","link":"https:\/\/giapsgk.com\/chuyen-de\/tong-hop-cong-thuc-toan-10-canh-dieu-hoc-ki-1-va-hoc-ki-2\/","title":{"rendered":"T\u1ed5ng h\u1ee3p c\u00f4ng th\u1ee9c To\u00e1n 10 C\u00e1nh di\u1ec1u h\u1ecdc k\u00ec 1 v\u00e0 h\u1ecdc k\u00ec 2"},"content":{"rendered":"<p data-start=\"425\" data-end=\"915\">Vi\u1ec7c ghi nh\u1edb v\u00e0 v\u1eadn d\u1ee5ng \u0111\u00fang <strong data-start=\"526\" data-end=\"551\">c\u00e1c c\u00f4ng th\u1ee9c To\u00e1n 10<\/strong> l\u00e0 y\u1ebfu t\u1ed1 then ch\u1ed1t \u0111\u1ec3 h\u1ecdc t\u1ed1t m\u00f4n h\u1ecdc n\u00e0y. Trong b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y, ch\u00fang t\u00f4i s\u1ebd <strong data-start=\"634\" data-end=\"675\">t\u1ed5ng h\u1ee3p to\u00e0n b\u1ed9 c\u00f4ng th\u1ee9c quan tr\u1ecdng<\/strong> c\u1ee7a ch\u01b0\u01a1ng tr\u00ecnh To\u00e1n 10 C\u00e1nh Di\u1ec1u, chia theo t\u1eebng ch\u01b0\u01a1ng: t\u1eeb m\u1ec7nh \u0111\u1ec1, t\u1eadp h\u1ee3p, h\u00e0m s\u1ed1 cho \u0111\u1ebfn vect\u01a1 v\u00e0 to\u1ea1 \u0111\u1ed9 trong h\u00ecnh h\u1ecdc ph\u1eb3ng. T\u00e0i li\u1ec7u ph\u00f9 h\u1ee3p \u0111\u1ec3 <strong data-start=\"816\" data-end=\"856\">\u00f4n t\u1eadp, l\u00e0m b\u00e0i ki\u1ec3m tra, thi h\u1ecdc k\u1ef3<\/strong> ho\u1eb7c d\u00f9ng nh\u01b0 m\u1ed9t b\u1ea3ng tra c\u1ee9u nhanh trong su\u1ed1t n\u0103m h\u1ecdc.<\/p>\n<h2><strong>Ch\u01b0\u01a1ng I. M\u1ec7nh \u0111\u1ec1 to\u00e1n h\u1ecdc. T\u1eadp h\u1ee3p<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-428 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-cong-thuc-toan-10-canh-dieu-hoc-ki-1-va-hoc-ki-2-1.png\" alt=\"T\u1ed5ng h\u1ee3p c\u00f4ng th\u1ee9c To\u00e1n 10 C\u00e1nh Di\u1ec1u theo t\u1eebng ch\u01b0\u01a1ng\" width=\"454\" height=\"462\" \/><\/p>\n<h2><strong>B\u00e0i 1. M\u1ec7nh \u0111\u1ec1 to\u00e1n h\u1ecdc<\/strong><\/h2>\n<p><strong>M\u1ec7nh \u0111\u1ec1:<\/strong> C\u00e2u kh\u1eb3ng \u0111\u1ecbnh \u0111\u00fang ho\u1eb7c sai (kh\u00f4ng v\u1eeba \u0111\u00fang v\u1eeba sai).<\/p>\n<p>M\u1ec7nh \u0111\u1ec1 ph\u1ee7 \u0111\u1ecbnh, m\u1ec7nh \u0111\u1ec1 k\u00e9o theo, m\u1ec7nh \u0111\u1ec1 \u0111\u1ea3o.<\/p>\n<p>M\u1ec7nh \u0111\u1ec1 \u0111\u00fang \u2194 ph\u1ee7 \u0111\u1ecbnh sai.<\/p>\n<h3><strong>B\u00e0i 2. T\u1eadp h\u1ee3p. C\u00e1c ph\u00e9p to\u00e1n tr\u00ean t\u1eadp h\u1ee3p<\/strong><\/h3>\n<p><strong>T\u1eadp h\u1ee3p:<\/strong> T\u1eadp h\u1ee3p l\u00e0 m\u1ed9t nh\u00f3m c\u00e1c \u0111\u1ed1i t\u01b0\u1ee3ng x\u00e1c \u0111\u1ecbnh.<\/p>\n<p><strong>K\u00fd hi\u1ec7u:<\/strong> \u2208 (thu\u1ed9c), \u2282 (con), \u2205 (r\u1ed7ng).<\/p>\n<p><strong>Ph\u00e9p to\u00e1n:<\/strong><\/p>\n<ul>\n<li><strong>Giao:<\/strong> $A \\cap B = \\{x | x \\in A \\text{ v\u00e0 } x \\in B\\}$<\/li>\n<li><strong>H\u1ee3p:<\/strong> $A \\cup B = \\{x | x \\in A \\text{ ho\u1eb7c } x \\in B\\}$<\/li>\n<li><strong>Hi\u1ec7u:<\/strong> $A \\setminus B = \\{x | x \\in A \\text{ v\u00e0 } x \\notin B\\}$<\/li>\n<\/ul>\n<h2><strong>Ch\u01b0\u01a1ng II. B\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh v\u00e0 h\u1ec7 b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh b\u1eadc nh\u1ea5t hai \u1ea9n<\/strong><\/h2>\n<h3><strong>B\u00e0i 1. B\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh b\u1eadc nh\u1ea5t hai \u1ea9n<\/strong><\/h3>\n<ul>\n<li><strong>D\u1ea1ng:<\/strong> $ax + by &lt; c$, $ax + by \\geq c$,&#8230;<\/li>\n<li><strong>Bi\u1ec3u di\u1ec5n h\u00ecnh h\u1ecdc:<\/strong> n\u1eeda m\u1eb7t ph\u1eb3ng.<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 2. H\u1ec7 b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh b\u1eadc nh\u1ea5t hai \u1ea9n<\/strong><\/h3>\n<ul>\n<li>L\u00e0 giao c\u1ee7a nhi\u1ec1u n\u1eeda m\u1eb7t ph\u1eb3ng.<\/li>\n<li>Nghi\u1ec7m l\u00e0 t\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m th\u1ecfa m\u00e3n t\u1ea5t c\u1ea3 c\u00e1c b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh.<\/li>\n<\/ul>\n<h2><strong>Ch\u01b0\u01a1ng III. H\u00e0m s\u1ed1 v\u00e0 \u0111\u1ed3 th\u1ecb<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-430 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-cong-thuc-toan-10-canh-dieu-hoc-ki-1-va-hoc-ki-2-2.png\" alt=\"C\u00e1c c\u00f4ng th\u1ee9c To\u00e1n l\u1edbp 10 C\u00e1nh Di\u1ec1u c\u1ea7n nh\u1edb\" width=\"572\" height=\"401\" \/><\/p>\n<h3><strong>B\u00e0i 1. H\u00e0m s\u1ed1 v\u00e0 \u0111\u1ed3 th\u1ecb<\/strong><\/h3>\n<ul>\n<li><strong>H\u00e0m s\u1ed1:<\/strong> M\u1ed7i $x \\in D$ x\u00e1c \u0111\u1ecbnh duy nh\u1ea5t $y = f(x)$.<\/li>\n<li><strong>H\u00e0m s\u1ed1 b\u1eadc nh\u1ea5t:<\/strong> $y = ax + b$; \u0111\u1ed3 th\u1ecb l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng.<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 2. H\u00e0m s\u1ed1 b\u1eadc hai. \u0110\u1ed3 th\u1ecb v\u00e0 \u1ee9ng d\u1ee5ng<\/strong><\/h3>\n<ul>\n<li><strong>D\u1ea1ng chu\u1ea9n:<\/strong> $y = ax^2 + bx + c$<\/li>\n<li><strong>\u0110\u1ec9nh:<\/strong> $x = -\\frac{b}{2a}$<\/li>\n<li><strong>Tr\u1ee5c \u0111\u1ed1i x\u1ee9ng:<\/strong> $x = -\\frac{b}{2a}$<\/li>\n<\/ul>\n<p>H\u1ec7 s\u1ed1 a x\u00e1c \u0111\u1ecbnh b\u1ec1 l\u00f5m (m\u1edf l\u00ean ho\u1eb7c xu\u1ed1ng).<\/p>\n<h3><strong>B\u00e0i 3. D\u1ea5u c\u1ee7a tam th\u1ee9c b\u1eadc hai<\/strong><\/h3>\n<p><strong>Tam th\u1ee9c:<\/strong> $f(x) = ax^2 + bx + c$<\/p>\n<p>X\u00e9t d\u1ea5u theo nghi\u1ec7m:<\/p>\n<ul>\n<li><strong>N\u1ebfu $\\Delta &gt; 0$:<\/strong> hai nghi\u1ec7m $x_1 &lt; x_2$, d\u00f9ng b\u1ea3ng x\u00e9t d\u1ea5u.<\/li>\n<li><strong>N\u1ebfu $\\Delta &lt; 0$:<\/strong> c\u00f9ng d\u1ea5u v\u1edbi a.<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 4. B\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh b\u1eadc hai m\u1ed9t \u1ea9n<\/strong><\/h3>\n<p>Gi\u1ea3i b\u1eb1ng b\u1ea3ng x\u00e9t d\u1ea5u c\u1ee7a tam th\u1ee9c b\u1eadc hai.<\/p>\n<h3><strong>B\u00e0i 5. Hai d\u1ea1ng ph\u01b0\u01a1ng tr\u00ecnh quy v\u1ec1 ph\u01b0\u01a1ng tr\u00ecnh b\u1eadc hai<\/strong><\/h3>\n<p>\u0110\u01b0a v\u1ec1 $ax^2 + bx + c = 0$ b\u1eb1ng bi\u1ebfn \u0111\u1ed5i ho\u1eb7c \u0111\u1eb7t \u1ea9n ph\u1ee5.<\/p>\n<h2><strong>Ch\u01b0\u01a1ng IV. H\u1ec7 th\u1ee9c l\u01b0\u1ee3ng trong tam gi\u00e1c. Vect\u01a1<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-431 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-cong-thuc-toan-10-canh-dieu-hoc-ki-1-va-hoc-ki-2-3.png\" alt=\"C\u00f4ng th\u1ee9c To\u00e1n 10 C\u00e1nh Di\u1ec1u h\u1ecdc k\u1ef3 1 v\u00e0 h\u1ecdc k\u1ef3 2\" width=\"603\" height=\"424\" \/><\/p>\n<h3><strong>B\u00e0i 1. Gi\u00e1 tr\u1ecb l\u01b0\u1ee3ng gi\u00e1c c\u1ee7a g\u00f3c; \u0110\u1ecbnh l\u00fd cosin, sin<\/strong><\/h3>\n<p>Gi\u00e1 tr\u1ecb l\u01b0\u1ee3ng gi\u00e1c: sin, cos, tan, cot t\u1eeb 0\u00b0 \u0111\u1ebfn 180\u00b0.<\/p>\n<ul>\n<li><strong>\u0110\u1ecbnh l\u00fd Cosin:<\/strong> $c^2 = a^2 + b^2 &#8211; 2ab\\cos C$<\/li>\n<li><strong>\u0110\u1ecbnh l\u00fd Sin:<\/strong> $\\frac{a}{\\sin A} = \\frac{b}{\\sin B} = \\frac{c}{\\sin C}$<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 2. Gi\u1ea3i tam gi\u00e1c<\/strong><\/h3>\n<p>\u00c1p d\u1ee5ng \u0111\u1ecbnh l\u00ed sin, cos \u0111\u1ec3 t\u00ecm c\u1ea1nh ho\u1eb7c g\u00f3c c\u00f2n thi\u1ebfu.<\/p>\n<h3><strong>B\u00e0i 3. Kh\u00e1i ni\u1ec7m vect\u01a1<\/strong><\/h3>\n<p><strong>Vect\u01a1:<\/strong> \u0111\u1ea1i l\u01b0\u1ee3ng c\u00f3 h\u01b0\u1edbng v\u00e0 \u0111\u1ed9 l\u1edbn.<\/p>\n<p><strong>K\u00fd hi\u1ec7u:<\/strong> $\\vec{AB}$, \u0111\u1ed9 d\u00e0i l\u00e0 $|\\vec{AB}|$<\/p>\n<h3><strong>B\u00e0i 4. T\u1ed5ng, hi\u1ec7u hai vect\u01a1<\/strong><\/h3>\n<p>Quy t\u1eafc h\u00ecnh b\u00ecnh h\u00e0nh.<\/p>\n<p>$\\vec{a} + \\vec{b}$, $\\vec{a} &#8211; \\vec{b}$<\/p>\n<h3><strong>B\u00e0i 5. T\u00edch c\u1ee7a vect\u01a1 v\u1edbi m\u1ed9t s\u1ed1<\/strong><\/h3>\n<p>$k\\vec{a}$: k\u00e9o d\u00e0i ho\u1eb7c \u0111\u1ea3o chi\u1ec1u vect\u01a1.<\/p>\n<p>C\u00f9ng ph\u01b0\u01a1ng n\u1ebfu t\u1ed3n t\u1ea1i $k$ sao cho $\\vec{b} = k\\vec{a}$<\/p>\n<h3><strong>B\u00e0i 6. T\u00edch v\u00f4 h\u01b0\u1edbng hai vect\u01a1<\/strong><\/h3>\n<ul>\n<li><strong>C\u00f4ng th\u1ee9c:<\/strong> $\\vec{a} \\cdot \\vec{b} = |\\vec{a}||\\vec{b}|\\cos\\theta$<\/li>\n<li>N\u1ebfu $\\vec{a} \\cdot \\vec{b} = 0$ \u2192 vu\u00f4ng g\u00f3c.<\/li>\n<\/ul>\n<h2><strong>Ch\u01b0\u01a1ng V. \u0110\u1ea1i s\u1ed1 t\u1ed5 h\u1ee3p<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-432 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-cong-thuc-toan-10-canh-dieu-hoc-ki-1-va-hoc-ki-2-4.png\" alt=\"To\u00e0n b\u1ed9 c\u00f4ng th\u1ee9c To\u00e1n 10 C\u00e1nh Di\u1ec1u ch\u01b0\u01a1ng tr\u00ecnh m\u1edbi\" width=\"529\" height=\"611\" \/><\/p>\n<h3><strong>B\u00e0i 1. Quy t\u1eafc c\u1ed9ng, nh\u00e2n, s\u01a1 \u0111\u1ed3 c\u00e2y<\/strong><\/h3>\n<ul>\n<li><strong>Quy t\u1eafc c\u1ed9ng:<\/strong> M\u1ed9t c\u00f4ng vi\u1ec7c c\u00f3 $m$ ho\u1eb7c $n$ c\u00e1ch th\u1ef1c hi\u1ec7n \u2192 t\u1ed5ng c\u1ed9ng $m + n$ c\u00e1ch.<\/li>\n<li><strong>Quy t\u1eafc nh\u00e2n:<\/strong> C\u00f3 $m$ c\u00e1ch v\u00e0 sau \u0111\u00f3 $n$ c\u00e1ch \u2192 t\u1ed5ng c\u1ed9ng $m \\times n$ c\u00e1ch.<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 2. Ho\u00e1n v\u1ecb, ch\u1ec9nh h\u1ee3p<\/strong><\/h3>\n<ul>\n<li><strong>Ho\u00e1n v\u1ecb n ph\u1ea7n t\u1eed:<\/strong> $P_n = n!$<\/li>\n<li><strong>Ch\u1ec9nh h\u1ee3p:<\/strong> $A_n^k = \\frac{n!}{(n &#8211; k)!}$<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 3. T\u1ed5 h\u1ee3p<\/strong><\/h3>\n<p><strong>T\u1ed5 h\u1ee3p ch\u1eadp k c\u1ee7a n:<\/strong> $C_n^k = \\frac{n!}{k!(n-k)!}$<\/p>\n<h3><strong>B\u00e0i 4. Nh\u1ecb th\u1ee9c Newton<\/strong><\/h3>\n<p><strong>Khai tri\u1ec3n:<\/strong> $(a + b)^n = \\sum_{k=0}^{n} C_n^k a^{n-k}b^k$<\/p>\n<h2><strong>Ch\u01b0\u01a1ng VI. M\u1ed9t s\u1ed1 y\u1ebfu t\u1ed1 th\u1ed1ng k\u00ea v\u00e0 x\u00e1c su\u1ea5t<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-433 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-cong-thuc-toan-10-canh-dieu-hoc-ki-1-va-hoc-ki-2-5.png\" alt=\"\u00d4n t\u1eadp c\u00f4ng th\u1ee9c To\u00e1n 10 C\u00e1nh Di\u1ec1u hi\u1ec7u qu\u1ea3\" width=\"584\" height=\"402\" \/><\/p>\n<h3><strong>B\u00e0i 1. S\u1ed1 g\u1ea7n \u0111\u00fang. Sai s\u1ed1<\/strong><\/h3>\n<ul>\n<li><strong>Sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i:<\/strong> $\\Delta = |x &#8211; x_0|$<\/li>\n<li><strong>Sai s\u1ed1 t\u01b0\u01a1ng \u0111\u1ed1i:<\/strong> $\\frac{\\Delta}{|x_0|}$<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 2. C\u00e1c s\u1ed1 \u0111\u1eb7c tr\u01b0ng \u0111o xu th\u1ebf trung t\u00e2m<\/strong><\/h3>\n<ul>\n<li><strong>Trung b\u00ecnh c\u1ed9ng: <\/strong>$\\bar{x} = \\frac{x_1 + x_2 + \\dots + x_n}{n}$<\/li>\n<li>Trung v\u1ecb, mode.<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 3. \u0110o m\u1ee9c \u0111\u1ed9 ph\u00e2n t\u00e1n<\/strong><\/h3>\n<ul>\n<li><strong>Ph\u01b0\u01a1ng sai:<\/strong> $s^2 = \\frac{1}{n}\\sum (x_i &#8211; \\bar{x})^2$<\/li>\n<li><strong>\u0110\u1ed9 l\u1ec7ch chu\u1ea9n:<\/strong> $s = \\sqrt{s^2}$<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 4. X\u00e1c su\u1ea5t trong tr\u00f2 ch\u01a1i<\/strong><\/h3>\n<p>X\u00e1c su\u1ea5t = $\\frac{\\text{s\u1ed1 tr\u01b0\u1eddng h\u1ee3p thu\u1eadn l\u1ee3i}}{\\text{s\u1ed1 tr\u01b0\u1eddng h\u1ee3p c\u00f3 th\u1ec3 x\u1ea3y ra}}$<\/p>\n<h3><strong>B\u00e0i 5. X\u00e1c su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1<\/strong><\/h3>\n<p>Bi\u1ebfn c\u1ed1 h\u1ee3p, giao, \u0111\u1ed1i.<\/p>\n<p>T\u00ednh x\u00e1c su\u1ea5t b\u1eb1ng t\u1ed5 h\u1ee3p, ph\u00e9p \u0111\u1ebfm.<\/p>\n<h2><strong>Ch\u01b0\u01a1ng VII. Ph\u01b0\u01a1ng ph\u00e1p t\u1ecda \u0111\u1ed9 trong m\u1eb7t ph\u1eb3ng<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-434 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-cong-thuc-toan-10-canh-dieu-hoc-ki-1-va-hoc-ki-2-6.png\" alt=\"C\u00f4ng th\u1ee9c quan tr\u1ecdng trong s\u00e1ch To\u00e1n 10 C\u00e1nh Di\u1ec1u\" width=\"725\" height=\"448\" \/><\/p>\n<h3><strong>B\u00e0i 1. T\u1ecda \u0111\u1ed9 c\u1ee7a vect\u01a1<\/strong><\/h3>\n<p>$\\vec{AB} = (x_B &#8211; x_A; y_B &#8211; y_A)$<\/p>\n<h3><strong>B\u00e0i 2. Bi\u1ec3u th\u1ee9c t\u1ecda \u0111\u1ed9 c\u00e1c ph\u00e9p to\u00e1n vect\u01a1<\/strong><\/h3>\n<ul>\n<li>$\\vec{a} \\pm \\vec{b} = (x_1 \\pm x_2; y_1 \\pm y_2)$<\/li>\n<li>$k\\vec{a} = (kx; ky)$<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 3. Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng<\/strong><\/h3>\n<p>D\u1ea1ng t\u1ed5ng qu\u00e1t: $Ax + By + C = 0$<\/p>\n<p>D\u1ea1ng tham s\u1ed1, \u0111o\u1ea1n ch\u1eafn.<\/p>\n<h3><strong>B\u00e0i 4. V\u1ecb tr\u00ed t\u01b0\u01a1ng \u0111\u1ed1i, g\u00f3c v\u00e0 kho\u1ea3ng c\u00e1ch<\/strong><\/h3>\n<ul>\n<li><strong>G\u00f3c gi\u1eefa hai \u0111\u01b0\u1eddng th\u1eb3ng:<\/strong> $\\tan \\theta = \\left|\\frac{a_1b_2 &#8211; a_2b_1}{a_1a_2 + b_1b_2}\\right|$<\/li>\n<li><strong>Kho\u1ea3ng c\u00e1ch t\u1eeb \u0111i\u1ec3m $M(x_0, y_0)$ \u0111\u1ebfn \u0111\u01b0\u1eddng $Ax + By + C = 0$:<\/strong> $d = \\frac{|Ax_0 + By_0 + C|}{\\sqrt{A^2 + B^2}}$<\/li>\n<\/ul>\n<h2><strong>B\u00e0i 5. Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng tr\u00f2n<\/strong><\/h2>\n<p><strong>D\u1ea1ng chu\u1ea9n: <\/strong>$(x &#8211; a)^2 + (y &#8211; b)^2 = R^2$<\/p>\n<h3><strong>B\u00e0i 6. Ba \u0111\u01b0\u1eddng conic<\/strong><\/h3>\n<ul>\n<li><strong>Parabol<\/strong>: $y = ax^2 + bx + c$<\/li>\n<li><strong>Elip:<\/strong> $\\frac{x^2}{a^2} + \\frac{y^2}{b^2} = 1$<\/li>\n<li><strong>Hyperbol:<\/strong> $\\frac{x^2}{a^2} &#8211; \\frac{y^2}{b^2} = 1$<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Vi\u1ec7c ghi nh\u1edb v\u00e0 v\u1eadn d\u1ee5ng \u0111\u00fang c\u00e1c c\u00f4ng th\u1ee9c To\u00e1n 10 l\u00e0 y\u1ebfu t\u1ed1 then ch\u1ed1t \u0111\u1ec3 h\u1ecdc t\u1ed1t m\u00f4n h\u1ecdc n\u00e0y. Trong b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y, ch\u00fang t\u00f4i s\u1ebd t\u1ed5ng h\u1ee3p to\u00e0n b\u1ed9 c\u00f4ng th\u1ee9c quan tr\u1ecdng c\u1ee7a ch\u01b0\u01a1ng tr\u00ecnh To\u00e1n 10 C\u00e1nh Di\u1ec1u, chia theo t\u1eebng ch\u01b0\u01a1ng: t\u1eeb m\u1ec7nh \u0111\u1ec1, t\u1eadp h\u1ee3p, &#8230; <a title=\"T\u1ed5ng h\u1ee3p c\u00f4ng th\u1ee9c To\u00e1n 10 C\u00e1nh di\u1ec1u h\u1ecdc k\u00ec 1 v\u00e0 h\u1ecdc k\u00ec 2\" class=\"read-more\" href=\"https:\/\/giapsgk.com\/chuyen-de\/tong-hop-cong-thuc-toan-10-canh-dieu-hoc-ki-1-va-hoc-ki-2\/\" aria-label=\"\u0110\u1ecdc th\u00eam v\u1ec1 T\u1ed5ng h\u1ee3p c\u00f4ng th\u1ee9c To\u00e1n 10 C\u00e1nh di\u1ec1u h\u1ecdc k\u00ec 1 v\u00e0 h\u1ecdc k\u00ec 2\">\u0110\u1ecdc ti\u1ebfp<\/a><\/p>\n","protected":false},"author":1,"featured_media":435,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[4],"tags":[],"class_list":["post-422","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ly-thuyet"],"_links":{"self":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts\/422","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/comments?post=422"}],"version-history":[{"count":5,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts\/422\/revisions"}],"predecessor-version":[{"id":436,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts\/422\/revisions\/436"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/media\/435"}],"wp:attachment":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/media?parent=422"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/categories?post=422"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/tags?post=422"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}