{"id":390,"date":"2025-07-21T10:17:58","date_gmt":"2025-07-21T10:17:58","guid":{"rendered":"https:\/\/giapsgk.com\/chuyen-de\/?p=390"},"modified":"2025-07-21T10:28:28","modified_gmt":"2025-07-21T10:28:28","slug":"he-thong-cac-cong-thuc-toan-11-chan-troi-sang-tao-hk1-va-hk2","status":"publish","type":"post","link":"https:\/\/giapsgk.com\/chuyen-de\/he-thong-cac-cong-thuc-toan-11-chan-troi-sang-tao-hk1-va-hk2\/","title":{"rendered":"H\u1ec7 th\u1ed1ng c\u00e1c c\u00f4ng th\u1ee9c to\u00e1n 11 ch\u00e2n tr\u1eddi s\u00e1ng t\u1ea1o hk1 v\u00e0 hk2"},"content":{"rendered":"<p>B\u1ea1n c\u1ea7n \u00f4n t\u1eadp nhanh <strong>c\u00e1c c\u00f4ng th\u1ee9c To\u00e1n 11 Ch\u00e2n tr\u1eddi s\u00e1ng t\u1ea1o<\/strong> cho ki\u1ec3m tra, thi h\u1ecdc k\u1ef3 1&amp; 2 hay \u00f4n cu\u1ed1i n\u0103m? T\u00e0i li\u1ec7u d\u01b0\u1edbi \u0111\u00e2y s\u1ebd gi\u00fap b\u1ea1n h\u1ec7 th\u1ed1ng to\u00e0n b\u1ed9 ki\u1ebfn th\u1ee9c theo t\u1eebng ch\u01b0\u01a1ng, bao g\u1ed3m <strong data-start=\"698\" data-end=\"755\">\u0111\u1ecbnh ngh\u0129a, kh\u00e1i ni\u1ec7m quan tr\u1ecdng v\u00e0 c\u00f4ng th\u1ee9c c\u1ea7n nh\u1edb<\/strong> c\u1ee7a t\u1eebng b\u00e0i h\u1ecdc trong s\u00e1ch gi\u00e1o khoa.<\/p>\n<p data-start=\"800\" data-end=\"1040\">\u0110\u01b0\u1ee3c bi\u00ean so\u1ea1n b\u00e1m s\u00e1t ch\u01b0\u01a1ng tr\u00ecnh To\u00e1n 11 \u2013 b\u1ed9 <strong data-start=\"849\" data-end=\"871\">Ch\u00e2n tr\u1eddi s\u00e1ng t\u1ea1o<\/strong>, n\u1ed9i dung n\u00e0y s\u1ebd h\u1ed7 tr\u1ee3 b\u1ea1n ghi nh\u1edb ki\u1ebfn th\u1ee9c nhanh ch\u00f3ng, d\u1ec5 tra c\u1ee9u, t\u1eeb \u0111\u00f3 n\u00e2ng cao kh\u1ea3 n\u0103ng v\u1eadn d\u1ee5ng gi\u1ea3i b\u00e0i t\u1eadp, luy\u1ec7n \u0111\u1ec1 v\u00e0 \u0111\u1ea1t \u0111i\u1ec3m cao trong c\u00e1c k\u1ef3 thi s\u1eafp t\u1edbi.<\/p>\n<h2><strong>Ch\u01b0\u01a1ng 1: H\u00e0m s\u1ed1 l\u01b0\u1ee3ng gi\u00e1c v\u00e0 ph\u01b0\u01a1ng tr\u00ecnh l\u01b0\u1ee3ng gi\u00e1c<\/strong><\/h2>\n<h3><strong>1. G\u00f3c l\u01b0\u1ee3ng gi\u00e1c<\/strong><\/h3>\n<p>G\u00f3c l\u01b0\u1ee3ng gi\u00e1c: L\u00e0 g\u00f3c t\u1ea1o b\u1edfi tia quay t\u1eeb v\u1ecb tr\u00ed ban \u0111\u1ea7u \u0111\u1ebfn v\u1ecb tr\u00ed cu\u1ed1i theo chi\u1ec1u quay (d\u01b0\u01a1ng: ng\u01b0\u1ee3c kim \u0111\u1ed3ng h\u1ed3).<\/p>\n<ul>\n<li><strong>\u0110\u01a1n v\u1ecb:<\/strong> radian (1 v\u00f2ng tr\u00f2n = $2\\pi$ rad).<\/li>\n<li><strong>S\u1ed1 \u0111o cung tr\u00f2n:<\/strong> $s = r \\cdot \\alpha$<\/li>\n<\/ul>\n<h3><strong>2. Gi\u00e1 tr\u1ecb l\u01b0\u1ee3ng gi\u00e1c<\/strong><\/h3>\n<p>Tr\u00ean \u0111\u01b0\u1eddng tr\u00f2n l\u01b0\u1ee3ng gi\u00e1c, v\u1edbi g\u00f3c $\\alpha$:<\/p>\n<ul>\n<li>$\\sin\\alpha$ l\u00e0 tung \u0111\u1ed9<\/li>\n<li>$\\cos\\alpha$ l\u00e0 ho\u00e0nh \u0111\u1ed9<\/li>\n<li>$\\tan\\alpha = \\frac{\\sin\\alpha}{\\cos\\alpha}, \\quad \\cot\\alpha = \\frac{\\cos\\alpha}{\\sin\\alpha}$<\/li>\n<\/ul>\n<h3><strong>3. C\u00f4ng th\u1ee9c l\u01b0\u1ee3ng gi\u00e1c<\/strong><\/h3>\n<p>$\\sin^2x + \\cos^2x = 1$<\/p>\n<p>$1 + \\tan^2x = \\frac{1}{\\cos^2x}$, $1 + \\cot^2x = \\frac{1}{\\sin^2x}$<\/p>\n<p>C\u00f4ng th\u1ee9c c\u1ed9ng:<\/p>\n<ul>\n<li>$\\sin(a \\pm b) = \\sin a \\cos b \\pm \\cos a \\sin b$<\/li>\n<li>$\\cos(a \\pm b) = \\cos a \\cos b \\mp \\sin a \\sin b$<\/li>\n<\/ul>\n<h3><strong>4. H\u00e0m s\u1ed1 l\u01b0\u1ee3ng gi\u00e1c<\/strong><\/h3>\n<p>H\u00e0m s\u1ed1 $y = \\sin x$, $y = \\cos x$, $y = \\tan x$, $y = \\cot x$<\/p>\n<ul>\n<li>Tu\u1ea7n ho\u00e0n: chu k\u1ef3 $2\\pi$ ho\u1eb7c $\\pi$<\/li>\n<li>T\u00ednh ch\u1eb5n\/l\u1ebb: sin v\u00e0 tan l\u00e0 l\u1ebb; cos v\u00e0 cot l\u00e0 ch\u1eb5n<\/li>\n<\/ul>\n<h3><strong>5. Ph\u01b0\u01a1ng tr\u00ecnh l\u01b0\u1ee3ng gi\u00e1c c\u01a1 b\u1ea3n<\/strong><\/h3>\n<ul>\n<li>$\\sin x = a \\Rightarrow x = \\arcsin a + 2k\\pi$ ho\u1eb7c $\\pi &#8211; \\arcsin a + 2k\\pi$<\/li>\n<li>$\\cos x = a \\Rightarrow x = \\pm \\arccos a + 2k\\pi$<\/li>\n<li>$\\tan x = a \\Rightarrow x = \\arctan a + k\\pi$<\/li>\n<\/ul>\n<h2><strong>Ch\u01b0\u01a1ng 2: D\u00e3y s\u1ed1 \u2013 C\u1ea5p s\u1ed1 c\u1ed9ng \u2013 C\u1ea5p s\u1ed1 nh\u00e2n<\/strong><\/h2>\n<h3><strong>1. D\u00e3y s\u1ed1<\/strong><\/h3>\n<p>L\u00e0 m\u1ed9t h\u00e0m s\u1ed1 x\u00e1c \u0111\u1ecbnh tr\u00ean t\u1eadp s\u1ed1 t\u1ef1 nhi\u00ean $\\mathbb{N}$<\/p>\n<p>K\u00ed hi\u1ec7u: $(u_n)$ ho\u1eb7c $u_1, u_2, &#8230;, u_n$<\/p>\n<h3><strong>2. C\u1ea5p s\u1ed1 c\u1ed9ng (CSC)<\/strong><\/h3>\n<p>D\u00e3y s\u1ed1 c\u00f3 c\u00f4ng sai kh\u00f4ng \u0111\u1ed5i: $u_{n+1} = u_n + d$<\/p>\n<p>C\u00f4ng th\u1ee9c:<\/p>\n<ul>\n<li>$u_n = u_1 + (n &#8211; 1)d$<\/li>\n<li>$S_n = \\frac{n}{2}(u_1 + u_n) = \\frac{n}{2}[2u_1 + (n &#8211; 1)d]$<\/li>\n<\/ul>\n<h3><strong>3. C\u1ea5p s\u1ed1 nh\u00e2n (CSN)<\/strong><\/h3>\n<p>D\u00e3y s\u1ed1 c\u00f3 c\u00f4ng b\u1ed9i kh\u00f4ng \u0111\u1ed5i: $u_{n+1} = u_n \\cdot q$<\/p>\n<p>C\u00f4ng th\u1ee9c:<\/p>\n<ul>\n<li>$u_n = u_1 \\cdot q^{n-1}$<\/li>\n<li>$S_n = u_1 \\cdot \\frac{q^n &#8211; 1}{q &#8211; 1}$ (n\u1ebfu $q \\neq 1$)<\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-398 alignnone size-medium\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-he-thong-cac-cong-thuc-toan-11-chan-troi-sang-tao-hk1-va-hk2-2.png\" alt=\"H\u00ecnh \u1ea3nh - he-thong-cac-cong-thuc-toan-11-chan-troi-sang-tao-hk1-va-hk2\" width=\"642\" height=\"406\" \/><\/p>\n<h2><strong>Ch\u01b0\u01a1ng 3: Gi\u1edbi h\u1ea1n \u2013 H\u00e0m s\u1ed1 li\u00ean t\u1ee5c<\/strong><\/h2>\n<h3><strong>1. Gi\u1edbi h\u1ea1n d\u00e3y s\u1ed1<\/strong><\/h3>\n<p>$\\lim_{n \\to \\infty} u_n = L$ n\u1ebfu $u_n$ ti\u1ebfn g\u1ea7n \u0111\u1ebfn $L$<\/p>\n<p>C\u00e1c d\u1ea1ng v\u00f4 h\u1ea1n: $+\\infty, -\\infty$<\/p>\n<h3><strong>2. Gi\u1edbi h\u1ea1n h\u00e0m s\u1ed1<\/strong><\/h3>\n<p>$\\lim_{x \\to a} f(x) = L$<\/p>\n<p>T\u00ednh b\u1eb1ng bi\u1ebfn \u0111\u1ed5i \u0111\u1ea1i s\u1ed1, chia b\u1eadc cao nh\u1ea5t, s\u1eed d\u1ee5ng h\u1eb1ng \u0111\u1eb3ng th\u1ee9c&#8230;<\/p>\n<h3><strong>3. H\u00e0m s\u1ed1 li\u00ean t\u1ee5c<\/strong><\/h3>\n<p>H\u00e0m s\u1ed1 $f(x)$ li\u00ean t\u1ee5c t\u1ea1i $x = a$ n\u1ebfu:<\/p>\n<ul>\n<li>$\\lim_{x \\to a} f(x)$ t\u1ed3n t\u1ea1i<\/li>\n<li>$f(a)$ x\u00e1c \u0111\u1ecbnh<\/li>\n<li>$\\lim_{x \\to a} f(x) = f(a)$<\/li>\n<\/ul>\n<h2><strong>Ch\u01b0\u01a1ng 4: H\u00ecnh h\u1ecdc kh\u00f4ng gian \u2013 Quan h\u1ec7 song song<\/strong><\/h2>\n<h3><strong>1. \u0110i\u1ec3m, \u0111\u01b0\u1eddng, m\u1eb7t ph\u1eb3ng trong kh\u00f4ng gian<\/strong><\/h3>\n<p>Bi\u1ec3u di\u1ec5n h\u00ecnh h\u1ecdc trong kh\u00f4ng gian 3D<\/p>\n<h3><strong>2. Hai \u0111\u01b0\u1eddng th\u1eb3ng song song<\/strong><\/h3>\n<p>Hai \u0111\u01b0\u1eddng $a \/\/ b$ n\u1ebfu kh\u00f4ng c\u1eaft nhau v\u00e0 c\u00f9ng n\u1eb1m trong m\u1eb7t ph\u1eb3ng<\/p>\n<h3><strong>3. \u0110\u01b0\u1eddng th\u1eb3ng v\u00e0 m\u1eb7t ph\u1eb3ng song song<\/strong><\/h3>\n<p>$d \/\/ (P)$ n\u1ebfu kh\u00f4ng c\u00f3 \u0111i\u1ec3m chung<\/p>\n<h3><strong>4. Hai m\u1eb7t ph\u1eb3ng song song<\/strong><\/h3>\n<p>$(P) \/\/ (Q)$ n\u1ebfu kh\u00f4ng giao nhau<\/p>\n<h3><strong>5. Ph\u00e9p chi\u1ebfu song song<\/strong><\/h3>\n<p>Chi\u1ebfu m\u1ed9t \u0111i\u1ec3m\/h\u00ecnh l\u00ean m\u1eb7t ph\u1eb3ng theo ph\u01b0\u01a1ng c\u1ed1 \u0111\u1ecbnh (th\u01b0\u1eddng l\u00e0 ph\u01b0\u01a1ng vu\u00f4ng g\u00f3c)<\/p>\n<h2><strong>Ch\u01b0\u01a1ng 5: Th\u1ed1ng k\u00ea \u2013 M\u1eabu s\u1ed1 li\u1ec7u gh\u00e9p nh\u00f3m<\/strong><\/h2>\n<h3><strong>S\u1ed1 trung b\u00ecnh:<\/strong><\/h3>\n<p>$\\overline{x} = \\frac{\\sum f_i x_i}{\\sum f_i}$<\/p>\n<ul>\n<li><strong>M\u1ed1t:<\/strong> Gi\u00e1 tr\u1ecb c\u00f3 t\u1ea7n s\u1ed1 l\u1edbn nh\u1ea5t<\/li>\n<li><strong>Trung v\u1ecb: Gi\u00e1 tr\u1ecb chia m\u1eabu s\u1ed1 li\u1ec7u th\u00e0nh hai ph\u1ea7n b\u1eb1ng nhau<\/strong><\/li>\n<li><strong>T\u1ee9 ph\u00e2n v\u1ecb:<\/strong> Chia d\u1eef li\u1ec7u th\u00e0nh 4 ph\u1ea7n b\u1eb1ng nhau<\/li>\n<\/ul>\n<h2><strong>Ch\u01b0\u01a1ng 6: H\u00e0m s\u1ed1 m\u0169 \u2013 L\u00f4garit<\/strong><\/h2>\n<h3><strong>1. L\u0169y th\u1eeba<\/strong><\/h3>\n<ul>\n<li>$a^x$ x\u00e1c \u0111\u1ecbnh v\u1edbi $a &gt; 0$<\/li>\n<li>$a^{x+y} = a^x \\cdot a^y$<\/li>\n<\/ul>\n<h3><strong>2. L\u00f4garit<\/strong><\/h3>\n<ul>\n<li>$\\log_a b = x \\Leftrightarrow a^x = b$<\/li>\n<\/ul>\n<p><strong>C\u00f4ng th\u1ee9c:<\/strong><\/p>\n<ul>\n<li>$\\log_a (bc) = \\log_a b + \\log_a c$<\/li>\n<li>$\\log_a \\left( \\frac{b}{c} \\right) = \\log_a b &#8211; \\log_a c$<\/li>\n<li>$\\log_a b^n = n \\log_a b$<\/li>\n<\/ul>\n<h3><strong>3. H\u00e0m s\u1ed1 m\u0169 \u2013 L\u00f4garit<\/strong><\/h3>\n<ul>\n<li>H\u00e0m m\u0169: $y = a^x$, \u0111\u1ed3ng bi\u1ebfn khi $a &gt; 1$<\/li>\n<li>H\u00e0m loga: $y = \\log_a x$, ngh\u1ecbch bi\u1ebfn khi $0 &lt; a &lt; 1$<\/li>\n<\/ul>\n<h3><strong>4. Ph\u01b0\u01a1ng tr\u00ecnh \u2013 BPT m\u0169 &amp; loga<\/strong><\/h3>\n<p>S\u1eed d\u1ee5ng bi\u1ebfn \u0111\u1ed5i t\u01b0\u01a1ng \u0111\u01b0\u01a1ng, \u0111\u1eb7t \u1ea9n ph\u1ee5, so s\u00e1nh loga&#8230;<\/p>\n<h2><strong>Ch\u01b0\u01a1ng 7: \u0110\u1ea1o h\u00e0m<\/strong><\/h2>\n<h3><strong>1. \u0110\u1ecbnh ngh\u0129a \u0111\u1ea1o h\u00e0m<\/strong><\/h3>\n<ul>\n<li>$f'(x) = \\lim\\limits_{h \\to 0} \\frac{f(x + h) &#8211; f(x)}{h}$<\/li>\n<\/ul>\n<h3><strong>2. Quy t\u1eafc \u0111\u1ea1o h\u00e0m<\/strong><\/h3>\n<ul>\n<li>$(c)&#8217; = 0, \\quad (x^n)&#8217; = nx^{n-1}$<\/li>\n<li>$(u \\pm v)&#8217; = u&#8217; \\pm v&#8217;$<\/li>\n<li>$(uv)&#8217; = u&#8217;v + uv&#8217;$<\/li>\n<li>$\\left( \\frac{u}{v} \\right)&#8217; = \\frac{u&#8217;v &#8211; uv&#8217;}{v^2}$<\/li>\n<li>$(f(g(x)))&#8217; = f'(g(x)) \\cdot g'(x)$<\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-399 alignnone size-medium\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-he-thong-cac-cong-thuc-toan-11-chan-troi-sang-tao-hk1-va-hk2-3.png\" alt=\"H\u00ecnh \u1ea3nh - he-thong-cac-cong-thuc-toan-11-chan-troi-sang-tao-hk1-va-hk2\" width=\"639\" height=\"679\" \/><\/p>\n<h2><strong>Ch\u01b0\u01a1ng 8: Vu\u00f4ng g\u00f3c \u2013 Kho\u1ea3ng c\u00e1ch \u2013 G\u00f3c trong kh\u00f4ng gian<\/strong><\/h2>\n<p><strong>Hai \u0111\u01b0\u1eddng th\u1eb3ng vu\u00f4ng g\u00f3c:<\/strong> N\u1ebfu giao nhau v\u00e0 t\u1ea1o g\u00f3c $90^\\circ$<\/p>\n<p><strong>\u0110\u01b0\u1eddng th\u1eb3ng vu\u00f4ng g\u00f3c m\u1eb7t ph\u1eb3ng:<\/strong> N\u1ebfu vu\u00f4ng g\u00f3c v\u1edbi m\u1ecdi \u0111\u01b0\u1eddng trong m\u1eb7t ph\u1eb3ng \u0111\u00f3<\/p>\n<p><strong>Hai m\u1eb7t ph\u1eb3ng vu\u00f4ng g\u00f3c:<\/strong> N\u1ebfu c\u00f3 giao tuy\u1ebfn v\u00e0 t\u1ea1o g\u00f3c vu\u00f4ng<\/p>\n<p><strong>Kho\u1ea3ng c\u00e1ch<\/strong><\/p>\n<p>T\u1eeb \u0111i\u1ec3m \u0111\u1ebfn m\u1eb7t ph\u1eb3ng: $d = \\frac{|Ax + By + Cz + D|}{\\sqrt{A^2 + B^2 + C^2}}$<\/p>\n<p><strong>G\u00f3c \u2013 Nh\u1ecb di\u1ec7n<\/strong><\/p>\n<ul>\n<li><strong>G\u00f3c gi\u1eefa \u0111\u01b0\u1eddng v\u00e0 m\u1eb7t:<\/strong> G\u00f3c gi\u1eefa \u0111\u01b0\u1eddng v\u00e0 h\u00ecnh chi\u1ebfu vu\u00f4ng g\u00f3c l\u00ean m\u1eb7t<\/li>\n<li><strong>G\u00f3c nh\u1ecb di\u1ec7n:<\/strong> G\u00f3c gi\u1eefa hai m\u1eb7t ph\u1eb3ng<\/li>\n<\/ul>\n<h2><strong>Ch\u01b0\u01a1ng 9: X\u00e1c su\u1ea5t<\/strong><\/h2>\n<h3><strong>1. X\u00e1c su\u1ea5t giao bi\u1ebfn c\u1ed1<\/strong><\/h3>\n<ul>\n<li>$P(A \\cap B) = P(A) \\cdot P(B|A)$<\/li>\n<\/ul>\n<h3><strong>2. X\u00e1c su\u1ea5t h\u1ee3p bi\u1ebfn c\u1ed1<\/strong><\/h3>\n<ul>\n<li>$P(A \\cup B) = P(A) + P(B) &#8211; P(A \\cap B)$<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>B\u1ea1n c\u1ea7n \u00f4n t\u1eadp nhanh c\u00e1c c\u00f4ng th\u1ee9c To\u00e1n 11 Ch\u00e2n tr\u1eddi s\u00e1ng t\u1ea1o cho ki\u1ec3m tra, thi h\u1ecdc k\u1ef3 1&amp; 2 hay \u00f4n cu\u1ed1i n\u0103m? T\u00e0i li\u1ec7u d\u01b0\u1edbi \u0111\u00e2y s\u1ebd gi\u00fap b\u1ea1n h\u1ec7 th\u1ed1ng to\u00e0n b\u1ed9 ki\u1ebfn th\u1ee9c theo t\u1eebng ch\u01b0\u01a1ng, bao g\u1ed3m \u0111\u1ecbnh ngh\u0129a, kh\u00e1i ni\u1ec7m quan tr\u1ecdng v\u00e0 c\u00f4ng th\u1ee9c c\u1ea7n nh\u1edb &#8230; <a title=\"H\u1ec7 th\u1ed1ng c\u00e1c c\u00f4ng th\u1ee9c to\u00e1n 11 ch\u00e2n tr\u1eddi s\u00e1ng t\u1ea1o hk1 v\u00e0 hk2\" class=\"read-more\" href=\"https:\/\/giapsgk.com\/chuyen-de\/he-thong-cac-cong-thuc-toan-11-chan-troi-sang-tao-hk1-va-hk2\/\" aria-label=\"\u0110\u1ecdc th\u00eam v\u1ec1 H\u1ec7 th\u1ed1ng c\u00e1c c\u00f4ng th\u1ee9c to\u00e1n 11 ch\u00e2n tr\u1eddi s\u00e1ng t\u1ea1o hk1 v\u00e0 hk2\">\u0110\u1ecdc ti\u1ebfp<\/a><\/p>\n","protected":false},"author":1,"featured_media":397,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[4],"tags":[],"class_list":["post-390","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ly-thuyet"],"_links":{"self":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts\/390","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/comments?post=390"}],"version-history":[{"count":7,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts\/390\/revisions"}],"predecessor-version":[{"id":400,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts\/390\/revisions\/400"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/media\/397"}],"wp:attachment":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/media?parent=390"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/categories?post=390"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/tags?post=390"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}