{"id":230,"date":"2025-07-19T09:39:47","date_gmt":"2025-07-19T09:39:47","guid":{"rendered":"https:\/\/giapsgk.com\/chuyen-de\/?p=230"},"modified":"2025-07-21T05:06:10","modified_gmt":"2025-07-21T05:06:10","slug":"tong-hop-kien-thuc-toan-12-canh-dieu-hk1-va-hk2","status":"publish","type":"post","link":"https:\/\/giapsgk.com\/chuyen-de\/tong-hop-kien-thuc-toan-12-canh-dieu-hk1-va-hk2\/","title":{"rendered":"T\u1ed5ng h\u1ee3p ki\u1ebfn th\u1ee9c To\u00e1n 12 C\u00e1nh di\u1ec1u HK1 v\u00e0 HK2"},"content":{"rendered":"<p>B\u1ea1n \u0111ang t\u00ecm ki\u1ebfm m\u1ed9t t\u00e0i li\u1ec7u t\u1ed5ng h\u1ee3p \u0111\u1ea7y \u0111\u1ee7 ki\u1ebfn th\u1ee9c To\u00e1n l\u1edbp 12 theo b\u1ed9 s\u00e1ch <strong data-start=\"1074\" data-end=\"1087\">C\u00e1nh di\u1ec1u<\/strong>? B\u00e0i vi\u1ebft n\u00e0y s\u1ebd gi\u00fap b\u1ea1n h\u1ec7 th\u1ed1ng to\u00e0n b\u1ed9 n\u1ed9i dung tr\u1ecdng t\u00e2m c\u1ee7a h\u1ecdc k\u1ef3 1 v\u00e0 h\u1ecdc k\u1ef3 2, b\u00e1m s\u00e1t ch\u01b0\u01a1ng tr\u00ecnh m\u1edbi c\u1ee7a B\u1ed9 GD&amp;\u0110T. M\u1ed7i ch\u01b0\u01a1ng h\u1ecdc \u0111\u01b0\u1ee3c tr\u00ecnh b\u00e0y r\u00f5 r\u00e0ng, c\u00f3 <strong data-start=\"1257\" data-end=\"1278\">t\u00f3m t\u1eaft l\u00fd thuy\u1ebft<\/strong>, <strong data-start=\"1280\" data-end=\"1301\">c\u00f4ng th\u1ee9c c\u1ea7n nh\u1edb<\/strong> v\u00e0 <strong data-start=\"1305\" data-end=\"1331\">d\u1ea1ng b\u00e0i t\u1eadp \u0111i\u1ec3n h\u00ecnh<\/strong>, h\u1ed7 tr\u1ee3 h\u1ecdc sinh \u00f4n luy\u1ec7n hi\u1ec7u qu\u1ea3 v\u00e0 chu\u1ea9n b\u1ecb t\u1ed1t nh\u1ea5t cho k\u1ef3 thi t\u1ed1t nghi\u1ec7p THPT. \u0110\u00e2y l\u00e0 t\u00e0i li\u1ec7u h\u1eefu \u00edch cho c\u1ea3 h\u1ecdc sinh, gi\u00e1o vi\u00ean v\u00e0 ph\u1ee5 huynh trong qu\u00e1 tr\u00ecnh h\u1ecdc t\u1eadp v\u00e0 \u00f4n thi.<\/p>\n<h2><strong>Ch\u01b0\u01a1ng 1: \u1ee8ng d\u1ee5ng \u0111\u1ea1o h\u00e0m \u0111\u1ec3 kh\u1ea3o s\u00e1t v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-239 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-kien-thuc-toan-12-canh-dieu-hk1-va-hk2-5.png\" alt=\"T\u1ed5ng h\u1ee3p ki\u1ebfn th\u1ee9c tr\u1ecdng t\u00e2m To\u00e1n 12 C\u00e1nh di\u1ec1u h\u1ecdc k\u1ef3 1 v\u00e0 h\u1ecdc k\u1ef3 2\" width=\"834\" height=\"426\" \/><\/p>\n<h3><strong>B\u00e0i 1. T\u00ednh \u0111\u01a1n \u0111i\u1ec7u c\u1ee7a h\u00e0m s\u1ed1<\/strong><\/h3>\n<ul>\n<li>H\u00e0m s\u1ed1 \u0111\u1ed3ng bi\u1ebfn tr\u00ean (a; b) \u21d4 $f'(x) &gt; 0$ \u2200 x \u2208 (a; b)<\/li>\n<li>H\u00e0m s\u1ed1 ngh\u1ecbch bi\u1ebfn tr\u00ean (a; b) \u21d4 $f'(x) &lt; 0$ \u2200 x \u2208 (a; b)<\/li>\n<\/ul>\n<p>B\u1ea3ng bi\u1ebfn thi\u00ean s\u1eed d\u1ee5ng \u0111\u1ea1o h\u00e0m \u0111\u1ec3 x\u00e1c \u0111\u1ecbnh chi\u1ec1u bi\u1ebfn thi\u00ean.<\/p>\n<h3><strong>B\u00e0i 2. Gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t \u2013 nh\u1ecf nh\u1ea5t c\u1ee7a h\u00e0m s\u1ed1<\/strong><\/h3>\n<ul>\n<li>V\u1edbi $f(x)$ li\u00ean t\u1ee5c tr\u00ean [a; b]: T\u00ednh $f'(x) = 0$ \u2192 t\u00ecm \u0111i\u1ec3m c\u1ef1c tr\u1ecb.<\/li>\n<li>So s\u00e1nh gi\u00e1 tr\u1ecb $f(a), f(b), f(c)$ \u0111\u1ec3 t\u00ecm GTLN, GTNN.<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 3. \u0110\u01b0\u1eddng ti\u1ec7m c\u1eadn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/strong><\/h3>\n<ul>\n<li><strong>Ti\u1ec7m c\u1eadn \u0111\u1ee9ng<\/strong> t\u1ea1i $x = a$ \u21d4 $\\lim_{x \\to a^-} f(x) = \\pm \\infty$ ho\u1eb7c $\\lim_{x \\to a^+} f(x) = \\pm \\infty$<\/li>\n<li><strong>Ti\u1ec7m c\u1eadn ngang:<\/strong> $\\lim_{x \\to \\pm\\infty} f(x) = L \\Rightarrow y = L$ l\u00e0 ti\u1ec7m c\u1eadn ngang.<\/li>\n<li><strong>Ti\u1ec7m c\u1eadn xi\u00ean:<\/strong> N\u1ebfu $\\lim_{x \\to \\infty} \\left[f(x) &#8211; (ax + b)\\right] = 0$ \u2192 $y = ax + b$ l\u00e0 ti\u1ec7m c\u1eadn xi\u00ean.<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 4. Kh\u1ea3o s\u00e1t v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/strong><\/h3>\n<p>Quy tr\u00ecnh kh\u1ea3o s\u00e1t:<\/p>\n<ul>\n<li><strong>B\u01b0\u1edbc 1<\/strong>. TX\u0110<\/li>\n<li><strong> B\u01b0\u1edbc 2<\/strong>. T\u1eadp gi\u00e1 tr\u1ecb<\/li>\n<li><strong> B\u01b0\u1edbc 3<\/strong>. Gi\u1edbi h\u1ea1n, ti\u1ec7m c\u1eadn<\/li>\n<li><strong> B\u01b0\u1edbc 4<\/strong>. \u0110\u1ea1o h\u00e0m \u2192 \u0111\u01a1n \u0111i\u1ec7u, c\u1ef1c tr\u1ecb<\/li>\n<li><strong> B\u01b0\u1edbc 5<\/strong>. \u0110\u1ea1o h\u00e0m c\u1ea5p 2 \u2192 l\u1ed3i l\u00f5m<\/li>\n<li><strong> B\u01b0\u1edbc 6<\/strong>. V\u1ebd b\u1ea3ng bi\u1ebfn thi\u00ean \u2192 \u0111\u1ed3 th\u1ecb<\/li>\n<\/ul>\n<h2><strong>Ch\u01b0\u01a1ng 2: T\u1ecda \u0111\u1ed9 vect\u01a1 trong kh\u00f4ng gian<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-238 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-kien-thuc-toan-12-canh-dieu-hk1-va-hk2-4.png\" alt=\"T\u1ed5ng h\u1ee3p c\u00f4ng th\u1ee9c v\u00e0 l\u00fd thuy\u1ebft To\u00e1n 12 C\u00e1nh di\u1ec1u theo ch\u01b0\u01a1ng tr\u00ecnh m\u1edbi\" width=\"582\" height=\"515\" \/><\/p>\n<h3><strong>B\u00e0i 1. Vect\u01a1 v\u00e0 ph\u00e9p to\u00e1n trong kh\u00f4ng gian<\/strong><\/h3>\n<p>Vect\u01a1 $\\vec{AB} = (x_B &#8211; x_A; y_B &#8211; y_A; z_B &#8211; z_A)$<\/p>\n<ul>\n<li><strong>C\u1ed9ng vect\u01a1:<\/strong> $\\vec{u} + \\vec{v} = (x_1 + x_2; y_1 + y_2; z_1 + z_2)$<\/li>\n<li><strong>Nh\u00e2n v\u1edbi s\u1ed1<\/strong>: $k\\vec{u} = (kx; ky; kz)$<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 2. T\u1ecda \u0111\u1ed9 c\u1ee7a vect\u01a1<\/strong><\/h3>\n<p>N\u1ebfu $A(x_A, y_A, z_A), B(x_B, y_B, z_B)$, th\u00ec: $\\vec{AB} = (x_B &#8211; x_A; y_B &#8211; y_A; z_B &#8211; z_A)$<\/p>\n<h3><strong>B\u00e0i 3. Bi\u1ec3u th\u1ee9c t\u1ecda \u0111\u1ed9 c\u00e1c ph\u00e9p to\u00e1n<\/strong><\/h3>\n<p><strong>\u0110\u1ed9 d\u00e0i vect\u01a1:<\/strong> $|\\vec{u}| = \\sqrt{x^2 + y^2 + z^2}$<\/p>\n<p><strong>T\u00edch v\u00f4 h\u01b0\u1edbng:<\/strong> $\\vec{u} \\cdot \\vec{v} = x_1x_2 + y_1y_2 + z_1z_2$<\/p>\n<p>G\u00f3c gi\u1eefa hai vect\u01a1: $\\cos\\theta = \\frac{\\vec{u} \\cdot \\vec{v}}{|\\vec{u}| |\\vec{v}|}$<\/p>\n<h2><strong>Ch\u01b0\u01a1ng 3: S\u1ed1 \u0111\u1eb7c tr\u01b0ng \u0111o m\u1ee9c \u0111\u1ed9 ph\u00e2n t\u00e1n<\/strong><\/h2>\n<h3><strong>B\u00e0i 1. Kho\u1ea3ng bi\u1ebfn thi\u00ean v\u00e0 t\u1ee9 ph\u00e2n v\u1ecb<\/strong><\/h3>\n<p>Kho\u1ea3ng bi\u1ebfn thi\u00ean = Gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t \u2013 nh\u1ecf nh\u1ea5t<\/p>\n<p>T\u1ee9 ph\u00e2n v\u1ecb:<\/p>\n<ul>\n<li>Q1: ph\u1ea7n t\u1eed \u1edf v\u1ecb tr\u00ed 25%<\/li>\n<li>Q3: ph\u1ea7n t\u1eed \u1edf v\u1ecb tr\u00ed 75%<\/li>\n<\/ul>\n<p>Kho\u1ea3ng t\u1ee9 ph\u00e2n v\u1ecb = $Q3 &#8211; Q1$<\/p>\n<h3><strong>B\u00e0i 2. Ph\u01b0\u01a1ng sai v\u00e0 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n<\/strong><\/h3>\n<p>Ph\u01b0\u01a1ng sai (s\u00b2): $ s^2 = \\frac{1}{n} \\sum_{i=1}^{n} (x_i &#8211; \\bar{x})^2 $<\/p>\n<p>\u0110\u1ed9 l\u1ec7ch chu\u1ea9n (s): $ s = \\sqrt{s^2} $<\/p>\n<p>Trong m\u1eabu gh\u00e9p nh\u00f3m: s\u1eed d\u1ee5ng c\u00f4ng th\u1ee9c c\u00f3 t\u1ea7n s\u1ed1 v\u00e0 gi\u00e1 tr\u1ecb gi\u1eefa kho\u1ea3ng.<\/p>\n<hr \/>\n<h2><strong>Ch\u01b0\u01a1ng 4: Nguy\u00ean h\u00e0m \u2013 T\u00edch ph\u00e2n<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-237 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-kien-thuc-toan-12-canh-dieu-hk1-va-hk2-3.png\" alt=\"Ki\u1ebfn th\u1ee9c c\u1ea7n nh\u1edb m\u00f4n To\u00e1n l\u1edbp 12 s\u00e1ch C\u00e1nh di\u1ec1u c\u1ea3 n\u0103m\" width=\"558\" height=\"317\" \/><\/p>\n<h3><strong>B\u00e0i 1. Nguy\u00ean h\u00e0m<\/strong><\/h3>\n<p><strong>\u0110\u1ecbnh ngh\u0129a:<\/strong> $F'(x) = f(x) \\Rightarrow F(x)$ l\u00e0 nguy\u00ean h\u00e0m c\u1ee7a $f(x)$<\/p>\n<p>$\\int f(x) dx = F(x) + C$<\/p>\n<h3><strong>B\u00e0i 2. B\u1ea3ng nguy\u00ean h\u00e0m c\u01a1 b\u1ea3n<\/strong><\/h3>\n<ul>\n<li>$\\int x^n dx = \\frac{x^{n+1}}{n+1} + C \\quad (n \\ne -1)$<\/li>\n<li>$\\int \\frac{1}{x} dx = \\ln|x| + C$<\/li>\n<li>$\\int e^x dx = e^x + C$<\/li>\n<li>$\\int \\cos x dx = \\sin x + C$, $\\int \\sin x dx = -\\cos x + C$<\/li>\n<\/ul>\n<h3><strong>B\u00e0i 3. T\u00edch ph\u00e2n<\/strong><\/h3>\n<p>$\\int_a^b f(x) dx = F(b) &#8211; F(a)$, v\u1edbi $F'(x) = f(x)$<\/p>\n<p><strong>T\u00ednh di\u1ec7n t\u00edch:<\/strong> $ S = \\int_a^b |f(x)| dx $<\/p>\n<h3><strong>B\u00e0i 4. \u1ee8ng d\u1ee5ng t\u00edch ph\u00e2n<\/strong><\/h3>\n<p>Di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1eefa 2 \u0111\u01b0\u1eddng: $ S = \\int_a^b |f(x) &#8211; g(x)| dx $<\/p>\n<p>Th\u1ec3 t\u00edch v\u1eadt th\u1ec3 tr\u00f2n xoay: $ V = \\pi \\int_a^b [f(x)]^2 dx $<\/p>\n<h2><strong>Ch\u01b0\u01a1ng 5: Ph\u01b0\u01a1ng tr\u00ecnh h\u00ecnh h\u1ecdc trong kh\u00f4ng gian<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-236 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-kien-thuc-toan-12-canh-dieu-hk1-va-hk2-2.png\" alt=\"\u00d4n t\u1eadp To\u00e1n 12 C\u00e1nh di\u1ec1u HK1 v\u00e0 HK2 theo t\u1eebng ch\u01b0\u01a1ng\" width=\"1141\" height=\"533\" \/><\/p>\n<h3><strong>B\u00e0i 1. Ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t ph\u1eb3ng<\/strong><\/h3>\n<p><strong>D\u1ea1ng t\u1ed5ng qu\u00e1t: <\/strong>$Ax + By + Cz + D = 0$, v\u1edbi $\\vec{n} = (A; B; C)$ l\u00e0 VTPT<\/p>\n<p><strong>M\u1eb7t ph\u1eb3ng \u0111i qua $M(x_0, y_0, z_0)$:<\/strong> $A(x &#8211; x_0) + B(y &#8211; y_0) + C(z &#8211; z_0) = 0$<\/p>\n<h3><strong>B\u00e0i 2. Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng<\/strong><\/h3>\n<p><strong>D\u1ea1ng tham s\u1ed1:<\/strong> $ \\begin{cases} x = x_0 + at \\\\ y = y_0 + bt \\\\ z = z_0 + ct \\end{cases} $<\/p>\n<p><strong>VTCP:<\/strong> $\\vec{u} = (a; b; c)$, \u0111i\u1ec3m $M_0(x_0, y_0, z_0)$<\/p>\n<h3><strong>B\u00e0i 3. Ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t c\u1ea7u<\/strong><\/h3>\n<p><strong>D\u1ea1ng chu\u1ea9n:<\/strong> $ (x &#8211; a)^2 + (y &#8211; b)^2 + (z &#8211; c)^2 = R^2 $<\/p>\n<p><strong>Trong \u0111\u00f3:<\/strong> t\u00e2m $I(a, b, c)$, b\u00e1n k\u00ednh $R$<\/p>\n<h2><strong>Ch\u01b0\u01a1ng 6: M\u1ed9t s\u1ed1 y\u1ebfu t\u1ed1 x\u00e1c su\u1ea5t<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-235 size-full\" src=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/giapsgk-tong-hop-kien-thuc-toan-12-canh-dieu-hk1-va-hk2-1.png\" alt=\"H\u1ec7 th\u1ed1ng ki\u1ebfn th\u1ee9c \u0111\u1ea1i s\u1ed1 - gi\u1ea3i t\u00edch To\u00e1n 12 C\u00e1nh di\u1ec1u \u0111\u1ea7y \u0111\u1ee7 v\u00e0 chi ti\u1ebft\" width=\"531\" height=\"299\" \/><\/p>\n<h3><strong>B\u00e0i 1. X\u00e1c su\u1ea5t c\u00f3 \u0111i\u1ec1u ki\u1ec7n<\/strong><\/h3>\n<p>$P(A|B) = \\frac{P(A \\cap B)}{P(B)}$<\/p>\n<h3><strong>B\u00e0i 2. X\u00e1c su\u1ea5t to\u00e0n ph\u1ea7n &amp; Bayes<\/strong><\/h3>\n<ul>\n<li><strong>X\u00e1c su\u1ea5t to\u00e0n ph\u1ea7n:<\/strong> $ P(A) = \\sum_{i=1}^{n} P(B_i) \\cdot P(A|B_i) $<\/li>\n<li><strong>C\u00f4ng th\u1ee9c Bayes:<\/strong> $ P(B_k|A) = \\frac{P(B_k) \\cdot P(A|B_k)}{\\sum_{i=1}^{n} P(B_i) \\cdot P(A|B_i)} $<\/li>\n<\/ul>\n<p style=\"text-align: center;\"><a href=\"https:\/\/giapsgk.com\/chuyen-de\/wp-content\/uploads\/GiapSGK.com-Cong-thuc-toan-sach-CANH-DIEU.pdf\">T\u1ea3i file pdf c\u00f4ng th\u1ee9c to\u00e1n 12 s\u00e1ch C\u00c1NH DI\u1ec0U<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>B\u1ea1n \u0111ang t\u00ecm ki\u1ebfm m\u1ed9t t\u00e0i li\u1ec7u t\u1ed5ng h\u1ee3p \u0111\u1ea7y \u0111\u1ee7 ki\u1ebfn th\u1ee9c To\u00e1n l\u1edbp 12 theo b\u1ed9 s\u00e1ch C\u00e1nh di\u1ec1u? B\u00e0i vi\u1ebft n\u00e0y s\u1ebd gi\u00fap b\u1ea1n h\u1ec7 th\u1ed1ng to\u00e0n b\u1ed9 n\u1ed9i dung tr\u1ecdng t\u00e2m c\u1ee7a h\u1ecdc k\u1ef3 1 v\u00e0 h\u1ecdc k\u1ef3 2, b\u00e1m s\u00e1t ch\u01b0\u01a1ng tr\u00ecnh m\u1edbi c\u1ee7a B\u1ed9 GD&amp;\u0110T. M\u1ed7i ch\u01b0\u01a1ng h\u1ecdc \u0111\u01b0\u1ee3c &#8230; <a title=\"T\u1ed5ng h\u1ee3p ki\u1ebfn th\u1ee9c To\u00e1n 12 C\u00e1nh di\u1ec1u HK1 v\u00e0 HK2\" class=\"read-more\" href=\"https:\/\/giapsgk.com\/chuyen-de\/tong-hop-kien-thuc-toan-12-canh-dieu-hk1-va-hk2\/\" aria-label=\"\u0110\u1ecdc th\u00eam v\u1ec1 T\u1ed5ng h\u1ee3p ki\u1ebfn th\u1ee9c To\u00e1n 12 C\u00e1nh di\u1ec1u HK1 v\u00e0 HK2\">\u0110\u1ecdc ti\u1ebfp<\/a><\/p>\n","protected":false},"author":1,"featured_media":240,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[4],"tags":[],"class_list":["post-230","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ly-thuyet"],"_links":{"self":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts\/230","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/comments?post=230"}],"version-history":[{"count":10,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts\/230\/revisions"}],"predecessor-version":[{"id":360,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/posts\/230\/revisions\/360"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/media\/240"}],"wp:attachment":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/media?parent=230"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/categories?post=230"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/tags?post=230"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}