{"id":612,"date":"2025-08-06T15:26:40","date_gmt":"2025-08-06T15:26:40","guid":{"rendered":"https:\/\/giapsgk.com\/chuyen-de\/?page_id=612"},"modified":"2025-08-06T15:26:40","modified_gmt":"2025-08-06T15:26:40","slug":"bai-tap-dao-dong-dieu-hoa","status":"publish","type":"page","link":"https:\/\/giapsgk.com\/chuyen-de\/dao-dong\/dao-dong-dieu-hoa\/bai-tap-dao-dong-dieu-hoa\/","title":{"rendered":"B\u00e0i t\u1eadp dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0"},"content":{"rendered":"

C\u00e2u 1. <\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a th\u00ec li \u0111\u1ed9, v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c l\u00e0 ba \u0111\u1ea1i l\u01b0\u1ee3ng bi\u1ebfn \u0111\u1ed5i nh\u01b0 nh\u1eefng h\u00e0m cosin c\u1ee7a th\u1eddi gian c\u00f3<\/p>\n

A. c\u00f9ng bi\u00ean \u0111\u1ed9.<\/p>\n

B. c\u00f9ng pha.<\/p>\n

C. c\u00f9ng t\u1ea7n s\u1ed1 g\u00f3c.<\/p>\n

D. c\u00f9ng pha ban \u0111\u1ea7u.<\/p>\n

C\u00e2u 2.<\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, m\u1ed1i li\u00ean h\u1ec7 gi\u1eefa li \u0111\u1ed9, v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c l\u00e0<\/p>\n

A. v\u1eadn t\u1ed1c v\u00e0 li \u0111\u1ed9 lu\u00f4n c\u00f9ng chi\u1ec1u.<\/p>\n

B. v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c lu\u00f4n tr\u00e1i chi\u1ec1u.<\/p>\n

C. Gia t\u1ed1c v\u00e0 li \u0111\u1ed9 lu\u00f4n tr\u00e1i d\u1ea5u.<\/p>\n

D. gia t\u1ed1c v\u00e0 li \u0111\u1ed9 lu\u00f4n c\u00f9ng d\u1ea5u.<\/p>\n

C\u00e2u 3.\u00a0<\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, v\u1eadn t\u1ed1c bi\u1ebfn \u0111\u1ed5i<\/p>\n

A. c\u00f9ng pha v\u1edbi gia t\u1ed1c.<\/p>\n

B. ng\u01b0\u1ee3c pha v\u1edbi gia t\u1ed1c.<\/p>\n

C. s\u1edbm pha \u03c0\/2 so v\u1edbi li \u0111\u1ed9.<\/p>\n

D. tr\u1ec5 pha \u03c0\/2 so v\u1edbi li \u0111\u1ed9.<\/p>\n

C\u00e2u 4.<\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, gia t\u1ed1c bi\u1ebfn \u0111\u1ed5i<\/p>\n

A. s\u1edbm pha \u03c0\/4 so v\u1edbi li \u0111\u1ed9.<\/p>\n

B. ng\u01b0\u1ee3c pha v\u1edbi li \u0111\u1ed9.<\/p>\n

C. s\u1edbm pha \u03c0\/2 so v\u1edbi li \u0111\u1ed9.<\/p>\n

D. tr\u1ec5 pha \u03c0\/2 so v\u1edbi v\u1eadn t\u1ed1c.<\/p>\n

C\u00e2u 5.<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi x = 5cos(\u03c0t + \u03c0\/2), v\u1edbi x t\u00ednh b\u1eb1ng cm v\u00e0 t t\u00ednh b\u1eb1ng gi\u00e2y. X\u00e1c \u0111\u1ecbnh pha ban \u0111\u1ea7u?<\/p>\n

A. 5 cm.<\/p>\n

B. \u03c0 rad\/s.<\/p>\n

C.\u00a0 \u03c0\/2 rad.<\/p>\n

D. (\u03c0t + \u03c0\/2) rad.<\/p>\n

C\u00e2u 6.<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi x = 5sin(\u03c0t \u00a0– \u03c0\/4), v\u1edbi x t\u00ednh b\u1eb1ng cm v\u00e0 t t\u00ednh b\u1eb1ng gi\u00e2y. X\u00e1c \u0111\u1ecbnh pha ban \u0111\u1ea7u?<\/p>\n

A. – \u03c0\/4 rad.<\/p>\n

B. \u03c0\/4 rad.<\/p>\n

C.\u00a0 \u03c0\/2 rad.<\/p>\n

D. – 3\u03c0\/4 rad.<\/p>\n

C\u00e2u 7.<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh x = Acos(\u03c9t + \u03c6). Khi v\u1eadn t\u1ed1c c\u1ee7a v\u1eadt c\u1ef1c \u0111\u1ea1i th\u00ec<\/p>\n

A. li \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i.<\/p>\n

B. li \u0111\u1ed9 c\u1ef1c ti\u1ec3u.<\/p>\n

C. gia t\u1ed1c c\u1ef1c \u0111\u1ea1i ho\u1eb7c c\u1ef1c ti\u1ec3u.<\/p>\n

D. gia t\u1ed1c b\u1eb1ng kh\u00f4ng.<\/p>\n

C\u00e2u 8.<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh x = 4cos(10\u221a2t + p\/6)cm. Khi v\u1eadt qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng theo chi\u1ec1u \u00e2m th\u00ec v\u1eadn t\u1ed1c c\u1ee7a v\u1eadt c\u00f3 gi\u00e1 tr\u1ecb<\/p>\n

A. 4 cm\/s.<\/p>\n

B. 40\u221a2 cm\/s.<\/p>\n

C. \u2013 40\u221a2 cm\/s.<\/p>\n

D. – 4 cm\/s.<\/p>\n

C\u00e2u 9.<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh x = 5cos(\u03c0t + \u03c0\/6) cm. Khi v\u1eadt \u1edf bi\u00ean \u0111\u1ed9 \u00e2m th\u00ec li \u0111\u1ed9 c\u00f3 gi\u00e1 tr\u1ecb bao nhi\u00eau?<\/p>\n

A. \u2013 5cm<\/p>\n

B. 2,5cm<\/p>\n

C. 0<\/p>\n

D. \u2013 2,5cm<\/p>\n

C\u00e2u 10.<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh x = 4cos(2\u03c0t – \u03c0\/6) cm. Khi v\u1eadt \u1edf bi\u00ean \u0111\u1ed9 \u00e2m th\u00ec v\u1eadn t\u1ed1c c\u00f3 gi\u00e1 tr\u1ecb bao nhi\u00eau?<\/p>\n

A. 0<\/p>\n

B. 8\u03c0 cm\/s<\/p>\n

C. \u2013 8\u03c0 cm\/s<\/p>\n

D. 4\u03c0 cm\/s<\/p>\n

C\u00e2u 11<\/strong>.M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh x = 2cos(3\u03c0t + \u03c0\/2), v\u1edbi x t\u00ednh b\u1eb1ng cm v\u00e0 t t\u00ednh b\u1eb1ng gi\u00e2y. Khi v\u1eadt \u1edf bi\u00ean \u0111\u1ed9 d\u01b0\u01a1ng th\u00ec li \u0111\u1ed9 c\u00f3 gi\u00e1 tr\u1ecb bao nhi\u00eau?<\/p>\n

A. \u2013 2 cm<\/p>\n

B. 6\u03c0 cm<\/p>\n

C.\u00a0 2 cm<\/p>\n

D. \u2013 6\u03c0 cm\/s<\/p>\n

C\u00e2u 12.<\/strong>Cho dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a sau x = 3cos(4pt \u2013 \u03c0\/6) + 3 cm. H\u00e3y x\u00e1c \u0111\u1ecbnh v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i c\u1ee7a dao \u0111\u1ed9ng?<\/p>\n

A. 12 cm\/s<\/p>\n

B. 12p cm\/s<\/p>\n

C. 12p + 3 cm\/s<\/p>\n

D. 14\u03c0 cm\/s.<\/p>\n

C\u00e2u 13<\/strong>.Gia t\u1ed1c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a b\u1eb1ng kh\u00f4ng khi<\/p>\n

A. li \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i.<\/p>\n

B. li \u0111\u1ed9 c\u1ef1c ti\u1ec3u.<\/p>\n

C. v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i ho\u1eb7c c\u1ef1c ti\u1ec3u.<\/p>\n

D. v\u1eadn t\u1ed1c b\u1eb1ng 0.<\/p>\n

C\u00e2u 14.<\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0, v\u1eadn t\u1ed1c bi\u1ebfn \u0111\u1ed5i \u0111i\u1ec1u ho\u00e0<\/p>\n

A. C\u00f9ng pha so v\u1edbi li \u0111\u1ed9.<\/p>\n

B. Ng\u01b0\u1ee3c pha so v\u1edbi li \u0111\u1ed9.<\/p>\n

C. S\u1edbm pha p\/2 so v\u1edbi li \u0111\u1ed9.<\/p>\n

D. Tr\u1ec5 pha p\/2 so v\u1edbi li \u0111\u1ed9.<\/p>\n

C\u00e2u 15.<\/strong>Bi\u1ebft pha ban \u0111\u1ea7u c\u1ee7a m\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, ta x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c:<\/p>\n

A. Qu\u1ef9 \u0111\u1ea1o dao \u0111\u1ed9ng.<\/p>\n

B. C\u00e1ch k\u00edch th\u00edch dao \u0111\u1ed9ng<\/p>\n

C. Chu k\u1ef3 v\u00e0 tr\u1ea1ng th\u00e1i dao \u0111\u1ed9ng.<\/p>\n

D. Chi\u1ec1u chuy\u1ec3n \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00fac ban \u0111\u1ea7u<\/p>\n

C\u00e2u 16.<\/strong>Dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 l\u00e0<\/p>\n

A. Chuy\u1ec3n \u0111\u1ed9ng c\u00f3 gi\u1edbi h\u1ea1n \u0111\u01b0\u1ee3c l\u1eb7p \u0111i l\u1eb7p l\u1ea1i nhi\u1ec1u l\u1ea7n quanh m\u1ed9t v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng.<\/p>\n

B. Dao \u0111\u1ed9ng m\u00e0 tr\u1ea1ng th\u00e1i chuy\u1ec3n \u0111\u1ed9ng c\u1ee7a v\u1eadt \u0111\u01b0\u1ee3c l\u1eb7p l\u1ea1i nh\u01b0 c\u0169 sau nh\u1eefng kho\u1ea3ng th\u1eddi gian b\u1eb1ng nhau.<\/p>\n

C. Dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 l\u00e0 dao \u0111\u1ed9ng \u0111\u01b0\u1ee3c m\u00f4 t\u1ea3 b\u1eb1ng \u0111\u1ecbnh lu\u1eadt h\u00ecnh sin ho\u1eb7c cosin.<\/p>\n

D. Dao \u0111\u1ed9ng tu\u00e2n theo \u0111\u1ecbnh lu\u1eadt h\u00ecnh tan ho\u1eb7c cotan.<\/p>\n

C\u00e2u 17.<\/strong>Trong dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0, gia t\u1ed1c bi\u1ebfn \u0111\u1ed5i<\/p>\n

A. Tr\u1ec5 pha p\/2 so v\u1edbi li \u0111\u1ed9.<\/p>\n

B. C\u00f9ng pha v\u1edbi so v\u1edbi li \u0111\u1ed9.<\/p>\n

C. Ng\u01b0\u1ee3c pha v\u1edbi v\u1eadn t\u1ed1c.<\/p>\n

D. S\u1edbm pha p\/2 so v\u1edbi v\u1eadn t\u1ed1c<\/p>\n

C\u00e2u 18<\/strong>.M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng tr\u00ecnh x = 6cos(\u03c9t) (cm). Dao \u0111\u1ed9ng c\u1ee7a ch\u1ea5t \u0111i\u1ec3m c\u00f3 bi\u00ean \u0111\u1ed9 l\u00e0<\/p>\n

A. 2 cm.<\/p>\n

B. 6 cm.<\/p>\n

C. 3 cm.<\/p>\n

D. 12 cm.<\/p>\n

C\u00e2u 19.<\/strong>M\u1ed9t v\u1eadt nh\u1ecf dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng tr\u00ecnh x = 5cos(\u03c9t + 0,5\u03c0) (cm). Pha ban \u0111\u1ea7u c\u1ee7a dao \u0111\u1ed9ng l\u00e0<\/p>\n

A. \u03c0.<\/p>\n

B. 0,5\u03c0.<\/p>\n

C. 0,25\u03c0.<\/p>\n

D. 1,5\u03c0<\/p>\n

C\u00e2u 20.<\/strong>M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng tr\u00ecnh x = 10cos2\u03c0t (cm) c\u00f3 pha t\u1ea1i th\u1eddi \u0111i\u1ec3m t l\u00e0<\/p>\n

A. 2\u03c0.<\/p>\n

B. 2\u03c0t.<\/p>\n

C. 0.<\/p>\n

D. \u03c0.<\/p>\n

C\u00e2u 21.<\/strong>Trong m\u1ed9t dao \u0111\u1ed9ng c\u01a1 \u0111i\u1ec1u h\u00f2a, nh\u1eefng \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0o sau \u0111\u00e2y c\u00f3 gi\u00e1 tr\u1ecb kh\u00f4ng thay \u0111\u1ed5i?<\/p>\n

A. Bi\u00ean \u0111\u1ed9 v\u00e0 t\u1ea7n s\u1ed1.<\/p>\n

B. Gia t\u1ed1c v\u00e0 li \u0111\u1ed9.<\/p>\n

C. Gia t\u1ed1c v\u00e0 t\u1ea7n s\u1ed1.<\/p>\n

D. Bi\u00ean \u0111\u1ed9 v\u00e0 li \u0111\u1ed9<\/p>\n

C\u00e2u 22.<\/strong>V\u1eadn t\u1ed1c c\u1ee7a v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c \u0111\u1ea1i khi<\/p>\n

A. V\u1eadt \u1edf v\u1ecb tr\u00ed c\u00f3 pha dao \u0111\u1ed9ng c\u1ef1c \u0111\u1ea1i.<\/p>\n

B. V\u1eadt \u1edf v\u1ecb tr\u00ed c\u00f3 li \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i.<\/p>\n

C. Gia t\u1ed1c c\u1ee7a v\u1eadt \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i.<\/p>\n

D. V\u1eadt \u1edf v\u1ecb tr\u00ed c\u00f3 li \u0111\u1ed9 b\u1eb1ng kh\u00f4ng.<\/p>\n

C\u00e2u 23<\/strong>.M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 khi \u0111i qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng:<\/p>\n

A. V\u1eadn t\u1ed1c c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c \u0111\u1ea1i, gia t\u1ed1c c\u00f3 \u0111\u1ed9 l\u1edbn b\u1eb1ng 0<\/p>\n

C. V\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c c\u00f3 \u0111\u1ed9 l\u1edbn b\u1eb1ng 0<\/p>\n

B. V\u1eadn t\u1ed1c c\u00f3 \u0111\u1ed9 l\u1edbn b\u1eb1ng 0, gia t\u1ed1c c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c \u0111\u1ea1i<\/p>\n

D. V\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c \u0111\u1ea1i<\/p>\n

C\u00e2u 24<\/strong>.Trong c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau, ph\u01b0\u01a1ng tr\u00ecnh n\u00e0o kh\u00f4ng bi\u1ec3u th\u1ecb cho dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a?<\/p>\n

A. x = 3tsin (100pt + p\/6) cm.<\/p>\n

B. x = 3sin5pt + 3cos5pt cm<\/p>\n

C. x = 5cospt + 1 cm.<\/p>\n

D. x = 2sin$^{2}$(2pt + p\/6) cm<\/p>\n

C\u00e2u 25.<\/strong>V\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh x = Acos(wt + j). \u0110\u1ed3 th\u1ecb bi\u1ec3u di\u1ec5n s\u1ef1 ph\u1ee5 thu\u1ed9c c\u1ee7a v\u1eadn t\u1ed1c dao \u0111\u1ed9ng v v\u00e0o li \u0111\u1ed9 x c\u00f3 d\u1ea1ng n\u00e0o<\/p>\n

A. \u0110\u01b0\u1eddng tr\u00f2n.<\/p>\n

B. \u0110\u01b0\u1eddng th\u1eb3ng.<\/p>\n

C. Elip<\/p>\n

D. Parabol.<\/p>\n

C\u00e2u 26<\/strong>.M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0, li \u0111\u1ed9 x, gia t\u1ed1c a. \u0110\u1ed3 th\u1ecb bi\u1ec3u di\u1ec5n s\u1ef1 ph\u1ee5 thu\u1ed9c c\u1ee7a li \u0111\u1ed9 x v\u00e0 gia t\u1ed1c a c\u00f3 d\u1ea1ng n\u00e0o?<\/p>\n

A. \u0110o\u1ea1n th\u1eb3ng \u0111i qua g\u1ed1c to\u1ea1 \u0111\u1ed9<\/p>\n

B. \u0110u\u1eddng th\u1eb3ng kh\u00f4ng qua g\u1ed1c to\u1ea1 \u0111\u1ed9<\/p>\n

C. \u0110u\u1eddng tr\u00f2n<\/p>\n

D. \u0110\u01b0\u1eddng hipepol<\/p>\n

C\u00e2u 27<\/strong>.M\u1ed9t v\u1eadt dao \u0111\u1ed9ng n\u1eb1m ngang tr\u00ean qu\u1ef9 \u0111\u1ea1o d\u00e0i 10 cm, t\u00ecm bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng.<\/p>\n

A. 10 cm<\/p>\n

B. 5 cm<\/p>\n

C. 8 cm<\/p>\n

D. 4cm<\/p>\n

C\u00e2u 28.<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng tr\u00ecnh x = 0,04cos(10pt \u2013 \u03c0\/4) (m). T\u00ednh t\u1ed1c \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i v\u00e0 gia t\u1ed1c c\u1ef1c \u0111\u1ea1i c\u1ee7a v\u1eadt.<\/p>\n

A. 4p m\/s; 40 m\/s$^{2}$<\/p>\n

B. 0,4p m\/s; 40 m\/s$^{2}$<\/p>\n

C. 40p m\/s; 4 m\/s$^{2}$<\/p>\n

D. 0,4p m\/s; 4m\/s$^{2}$<\/p>\n

C\u00e2u 29<\/strong>.M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng x = 5cos(2pt + \u03c0\/3) cm. X\u00e1c \u0111\u1ecbnh gia t\u1ed1c c\u1ee7a v\u1eadt khi x = 3 cm.<\/p>\n

A. – 12m\/s$^{2}$<\/p>\n

B. – 120 cm\/s$^{2}$<\/p>\n

C. 1,2 m\/s$^{2}$<\/p>\n

D. – 60 m\/s$^{2}$<\/p>\n

C\u00e2u 30.<\/strong>V\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh: x = 20cos(2pt – p\/2) (cm). Gia t\u1ed1c c\u1ee7a v\u1eadt t\u1ea1i th\u1eddi \u0111i\u1ec3m t = 1\/12 s l\u00e0<\/p>\n

A. – 4 m\/s$^{2}$<\/p>\n

B. 2 m\/s$^{2}$<\/p>\n

C. 9,8 m\/s$^{2}$<\/p>\n

D. 10 m\/s$^{2}$<\/p>\n

C\u00e2u 31<\/strong>.M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a li \u0111\u1ed9: x = A sin(w t+j). Bi\u1ec3u th\u1ee9c gia t\u1ed1c c\u1ee7a v\u1eadt l\u00e0<\/p>\n

A. a = -w$^{2}$ x<\/p>\n

B. a = -w$^{2}$v<\/p>\n

C. a = -w$^{2}$x.sin(wt + j)<\/p>\n

D. a = – w$^{2}$A<\/p>\n

C\u00e2u 32.<\/strong>M\u00f4t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 A = 8 cm, t\u00ecm pha dao \u0111\u1ed9ng \u1ee9ng v\u1edbi li \u0111\u1ed9 x = 4 cm<\/p>\n

A. 2\u03c0\/3.<\/p>\n

B. \u00b1 \u03c0\/3<\/p>\n

C. \u03c0\/6<\/p>\n

D. 5\u03c0\/6.<\/p>\n

C\u00e2u 33<\/strong>.M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a tr\u00ean tr\u1ee5c Ox c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh x = 8cos(pt + \u03c0\/4) (x t\u00ednh b\u1eb1ng cm, t t\u00ednh b\u1eb1ng s) th\u00ec<\/p>\n

A. l\u00fac t = 0 ch\u1ea5t \u0111i\u1ec3m chuy\u1ec3n \u0111\u1ed9ng theo chi\u1ec1u (-) c\u1ee7a tr\u1ee5c Ox.<\/p>\n

B. ch\u1ea5t \u0111i\u1ec3m chuy\u1ec3n \u0111\u1ed9ng tr\u00ean \u0111o\u1ea1n th\u1eb3ng d\u00e0i 8 cm.<\/p>\n

C. chu k\u00ec dao \u0111\u1ed9ng l\u00e0 4s.<\/p>\n

D. v\u1eadn t\u1ed1c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m t\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng l\u00e0 8 cm\/s.<\/p>\n

C\u00e2u 34<\/strong>.N\u00f3i v\u1ec1 m\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, ph\u00e1t bi\u1ec3u n\u00e0o d\u01b0\u1edbi \u0111\u00e2y \u0111\u00fang?<\/p>\n

A. \u1ede v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, ch\u1ea5t \u0111i\u1ec3m c\u00f3 v\u1eadn t\u1ed1c b\u1eb1ng kh\u00f4ng v\u00e0 gia t\u1ed1c c\u1ef1c \u0111\u1ea1i.<\/p>\n

B. \u1ede v\u1ecb tr\u00ed bi\u00ean, ch\u1ea5t \u0111i\u1ec3m c\u00f3 v\u1eadn t\u1ed1c b\u1eb1ng kh\u00f4ng v\u00e0 gia t\u1ed1c b\u1eb1ng kh\u00f4ng.<\/p>\n

C. \u1ede v\u1ecb tr\u00ed bi\u00ean, ch\u1ea5t \u0111i\u1ec3m c\u00f3 \u0111\u1ed9 l\u1edbn v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i v\u00e0 gia t\u1ed1c c\u1ef1c \u0111\u1ea1i.<\/p>\n

D. \u1ede v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, ch\u1ea5t \u0111i\u1ec3m c\u00f3 \u0111\u1ed9 l\u1edbn v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i v\u00e0 gia t\u1ed1c b\u1eb1ng kh\u00f4ng.<\/p>\n

C\u00e2u 35.<\/strong>Khi m\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, chuy\u1ec3n \u0111\u1ed9ng c\u1ee7a v\u1eadt t\u1eeb v\u1ecb tr\u00ed bi\u00ean v\u1ec1 v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng l\u00e0<\/p>\n

chuy\u1ec3n \u0111\u1ed9ng<\/p>\n

A. ch\u1eadm d\u1ea7n \u0111\u1ec1u.<\/p>\n

B. ch\u1eadm d\u1ea7n.<\/p>\n

C. nhanh d\u1ea7n \u0111\u1ec1u.<\/p>\n

D. nhanh d\u1ea7n<\/p>\n

C\u00e2u 36.<\/strong>M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 tr\u00ean tr\u1ee5c Ox. Khi \u0111i t\u1eeb v\u1ecb tr\u00ed bi\u00ean v\u1ec1 v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng th\u00ec<\/p>\n

A. \u0111\u1ed9ng n\u0103ng c\u1ee7a ch\u1ea5t \u0111i\u1ec3m gi\u1ea3m.<\/p>\n

B. \u0111\u1ed9 l\u1edbn v\u1eadn t\u1ed1c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m gi\u1ea3m.<\/p>\n

C. \u0111\u1ed9 l\u1edbn li \u0111\u1ed9 c\u1ee7a ch\u1ea5t \u0111i\u1ec3m t\u0103ng.<\/p>\n

D. \u0111\u1ed9 l\u1edbn gia t\u1ed1c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m gi\u1ea3m.<\/p>\n

C\u00e2u 37.<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u00f3 qu\u1ef9 \u0111\u1ea1o l\u00e0 m\u1ed9t \u0111o\u1ea1n th\u1eb3ng d\u00e0i 10cm. Bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0<\/p>\n

A. 2,5cm.<\/p>\n

B. 5cm.<\/p>\n

C. 10cm.<\/p>\n

D. 12,5cm.<\/p>\n

C\u00e2u 38.<\/strong>Li \u0111\u1ed9 c\u1ee7a m\u1ed9t v\u1eadt ph\u1ee5 thu\u1ed9c v\u00e0o th\u1eddi gian theo ph\u01b0\u01a1ng tr\u00ecnh x = 12sin\u03c9t – 16sin$^{3}$\u03c9t. N\u1ebfu v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 th\u00ec gia t\u1ed1c c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c \u0111\u1ea1i l\u00e0<\/p>\n

A. 12\u03c9$^{2}$.<\/p>\n

B. 24\u03c9$^{2}$.<\/p>\n

C. 36\u03c9$^{2}$.<\/p>\n

D. 48\u03c9$^{2}$.<\/p>\n

C\u00e2u 39.<\/strong>K\u1ebft lu\u1eadn n\u00e0o sau \u0111\u00e2y l\u00e0 sai? M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a tr\u00ean tr\u1ee5c Ox v\u1edbi bi\u00ean \u0111\u1ed9 A th\u00ec:<\/p>\n

A. V\u1eadn t\u1ed1c c\u00f3 gi\u00e1 tr\u1ecb d\u01b0\u01a1ng khi v\u1eadt \u0111i t\u1eeb \u0111i\u1ec3m c\u00f3 li \u0111\u1ed9 -A \u0111\u1ebfn \u0111i\u1ec3m c\u00f3 li \u0111\u1ed9 +A<\/p>\n

B. Gia t\u1ed1c c\u00f3 gi\u00e1 tr\u1ecb d\u01b0\u01a1ng khi v\u1eadt \u0111i t\u1eeb \u0111i\u1ec3m c\u00f3 li \u0111\u1ed9 -A \u0111\u1ebfn \u0111i\u1ec3m c\u00f3 li \u0111\u1ed9 0<\/p>\n

C. Gia t\u1ed1c v\u00e0 v\u1eadn t\u1ed1c c\u00f3 gi\u00e1 tr\u1ecb d\u01b0\u01a1ng khi v\u1eadt \u0111i t\u1eeb \u0111i\u1ec3m c\u00f3 li \u0111\u1ed9 -A \u0111\u1ebfn \u0111i\u1ec3m c\u00f3 li \u0111\u1ed9 0<\/p>\n

D. Gia t\u1ed1c v\u00e0 v\u1eadn t\u1ed1c c\u00f3 gi\u00e1 tr\u1ecb d\u01b0\u01a1ng khi v\u1eadt \u0111i t\u1eeb \u0111i\u1ec3m c\u00f3 li \u0111\u1ed9 -A \u0111\u1ebfn \u0111i\u1ec3m c\u00f3 li \u0111\u1ed9 +A<\/p>\n

C\u00e2u 40.<\/strong>T\u00ecm ph\u00e1t bi\u1ec3u \u0111\u00fang v\u1ec1 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a?<\/p>\n

A. Trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a v\u1eadt gia t\u1ed1c lu\u00f4n c\u00f9ng pha v\u1edbi li \u0111\u1ed9<\/p>\n

B. Trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a v\u1eadt gia t\u1ed1c lu\u00f4n ng\u01b0\u1ee3c pha v\u1edbi v\u1eadn t\u1ed1c<\/p>\n

C. Trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a v\u1eadt gia t\u1ed1c lu\u00f4n c\u00f9ng pha v\u1edbi v\u1eadn t\u1ed1c<\/p>\n

D. kh\u00f4ng c\u00f3 ph\u00e1t bi\u1ec3u \u0111\u00fang<\/p>\n

C\u00e2u 41.<\/strong>Gia t\u1ed1c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a b\u1eb1ng kh\u00f4ng khi<\/p>\n

A. li \u0111\u1ed9 c\u1ef1c \u0111\u1ea1i<\/p>\n

B. li \u0111\u1ed9 c\u1ef1c ti\u1ec3u<\/p>\n

C. v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i ho\u1eb7c c\u1ef1c ti\u1ec3u<\/p>\n

D. v\u1eadn t\u1ed1c b\u1eb1ng 0<\/p>\n

C\u00e2u 42.<\/strong>M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u ho\u00e0 c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh x = – 10cos(\u03c0t + \u03c0\/5) cm. Khi v\u1eadt \u1edf bi\u00ean \u0111\u1ed9 d\u01b0\u01a1ng th\u00ec gia t\u1ed1c c\u00f3 gi\u00e1 tr\u1ecb bao nhi\u00eau?<\/p>\n

A. 10 cm\/s$^{2}$<\/p>\n

B.\u00a0 10\u03c0$^{2}$ cm\/s$^{2}$<\/p>\n

C. 10\u03c0 cm\/s$^{2}$<\/p>\n

D. – 10\u03c0$^{2}$ cm\/s$^{2}$<\/p>\n

C\u00e2u 43<\/strong>.Bi\u1ebft pha ban \u0111\u1ea7u c\u1ee7a m\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, ta x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c:<\/p>\n

A. Qu\u1ef9 \u0111\u1ea1o dao \u0111\u1ed9ng<\/p>\n

B. C\u00e1ch k\u00edch th\u00edch dao \u0111\u1ed9ng<\/p>\n

C. Chu k\u1ef3 v\u00e0 tr\u1ea1ng th\u00e1i dao \u0111\u1ed9ng<\/p>\n

D. Chi\u1ec1u chuy\u1ec3n \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00fac ban \u0111\u1ea7u<\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 1. Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a th\u00ec li \u0111\u1ed9, v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c l\u00e0 ba \u0111\u1ea1i l\u01b0\u1ee3ng bi\u1ebfn \u0111\u1ed5i nh\u01b0 nh\u1eefng h\u00e0m cosin c\u1ee7a th\u1eddi gian c\u00f3 A. c\u00f9ng bi\u00ean \u0111\u1ed9. B. c\u00f9ng pha. C. c\u00f9ng t\u1ea7n s\u1ed1 g\u00f3c. D. c\u00f9ng pha ban \u0111\u1ea7u. C\u00e2u 2.Trong dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, m\u1ed1i li\u00ean h\u1ec7 … \u0110\u1ecdc ti\u1ebfp<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":580,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-612","page","type-page","status-publish"],"_links":{"self":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages\/612","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/comments?post=612"}],"version-history":[{"count":2,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages\/612\/revisions"}],"predecessor-version":[{"id":626,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages\/612\/revisions\/626"}],"up":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages\/580"}],"wp:attachment":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/media?parent=612"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}