{"id":583,"date":"2025-08-04T10:04:16","date_gmt":"2025-08-04T10:04:16","guid":{"rendered":"https:\/\/giapsgk.com\/chuyen-de\/?page_id=583"},"modified":"2025-08-04T10:19:06","modified_gmt":"2025-08-04T10:19:06","slug":"nhan-dang-dao-dong-dieu-hoa","status":"publish","type":"page","link":"https:\/\/giapsgk.com\/chuyen-de\/dao-dong\/dao-dong-dieu-hoa\/nhan-dang-dao-dong-dieu-hoa\/","title":{"rendered":"Nh\u1eadn d\u1ea1ng dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a"},"content":{"rendered":"

\"H\u00ecnh<\/p>\n

V\u00ed d\u1ee5 1:<\/strong> \u00a0Dao \u0111\u1ed9ng c\u1ee7a v\u1eadt \u0111\u01b0\u1ee3c m\u00f4 t\u1ea3 b\u1eb1ng ph\u01b0\u01a1ng tr\u00ecnh x\u201d + 16x = 0. H\u00e3y x\u00e1c \u0111\u1ecbnh t\u1ea7n s\u1ed1 g\u00f3c \u03c9 c\u1ee7a v\u1eadt?<\/p>\n

A. 16 rad\/s.<\/p>\n

B. 8 rad\/s.<\/p>\n

C. 4 rad\/s.<\/p>\n

D. 10 rad\/s.<\/p>\n

Gi\u1ea3i<\/strong><\/p>\n

Theo \u0111\u1ec1: x\u201d + 16x = 0 \u2192 \u03c92<\/sup> = 16 \u2192 \u03c9 = 4 rad\/s.<\/p>\n

Ch\u1ecdn B.<\/p>\n

V\u00ed d\u1ee5 2<\/strong>: M\u1ed9t v\u1eadt dao \u0111\u1ed9ng tr\u00ean tr\u1ee5c Ox v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh \u0111\u1ed9ng l\u1ef1c h\u1ecdc c\u00f3 d\u1ea1ng 16x + 25x\u201d = 0. K\u1ebft lu\u1eadn \u0111\u00fang l\u00e0<\/p>\n

A. Dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0 \u0111i\u1ec1u h\u00f2a v\u1edbi t\u1ea7n s\u1ed1 g\u00f3c \u03c9 = 25 rad\/s.<\/p>\n

B. Dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0 \u0111i\u1ec1u h\u00f2a v\u1edbi t\u1ea7n s\u1ed1 g\u00f3c \u03c9 = 0,8 rad\/s.<\/p>\n

C. Dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0 tu\u1ea7n ho\u00e0n v\u1edbi t\u1ea7n s\u1ed1 g\u00f3c \u03c9 = 1,25 rad\/s.<\/p>\n

D. Dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0 \u0111i\u1ec1u h\u00f2a v\u1edbi t\u1ea7n s\u1ed1 g\u00f3c \u03c9 = 16 rad\/s.<\/p>\n

Gi\u1ea3i<\/strong><\/p>\n

$16x+25x”=0\\leftrightarrow x”+\\frac{16}{25}x=0\\to {{\\omega }^{2}}=\\frac{16}{25}\\to \\omega =0,8\\left( rad\/s \\right)$<\/p>\n

Ch\u1ecdn B<\/p>\n

V\u00ed d\u1ee5 3:<\/strong> Dao \u0111\u1ed9ng c\u1ee7a v\u1eadt \u0111\u01b0\u1ee3c m\u00f4 t\u1ea3 b\u1eb1ng ph\u01b0\u01a1ng tr\u00ecnh x\u201d + \u03c92<\/sup>x = 0. Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a v\u1eadt c\u00f3 th\u1ec3 l\u00e0<\/p>\n

A. x = 3t.sin(\u03c0\/3 \u2013 10t) cm<\/p>\n

B. x = 5t.cos(10t + \u03c0\/2) cm<\/p>\n

C. x = 5t2<\/sup>.sin(10t + \u03c0\/2) cm<\/p>\n

D. x = 2cos(10).sin(10t \u2013 \u03c0\/2) cm<\/p>\n

Gi\u1ea3i<\/strong><\/p>\n

V\u00ec ph\u01b0\u01a1ng tr\u00ecnh m\u00f4 t\u1ea3 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0 x\u201d + \u03c92<\/sup>x = 0 n\u00ean v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a x = Acos(\u03c9t + \u03c6)<\/p>\n

( v\u1edbi \u03c9 > 0; A > 0. Do t\u00ednh ch\u1ea5t tu\u1ea7n ho\u00e0n n\u00ean gi\u00e1 tr\u1ecb c\u1ee7a \u03c6: – \u03c0 < \u03c6 \u2264 \u03c0)<\/p>\n

– A. x = 3t.sin(\u03c0\/3 \u2013 10t) cm \u2192 A = 3t: lo\u1ea1i.<\/p>\n

– B. x = 5t.cos(10t + \u03c0\/2) cm\u2192 A = 5t: lo\u1ea1i<\/p>\n

– C. x = 5t2<\/sup>.sin(10t + \u03c0\/2) cm \u2192 A = 5t2<\/sup>: lo\u1ea1i<\/p>\n

– D. x = 2cos(10).sin(10t \u2013 \u03c0\/2) = 2cos(10).cos(10t \u2013 \u03c0) cm = 2cos(10).cos(10t + \u03c0) cm<\/p>\n

\u2192 A = 2cos(10) l\u00e0 h\u1eb1ng s\u1ed1 v\u00e0 \u03c9 = 10 rad\/s\u00a0; \u03c6 = \u03c0 rad<\/p>\n

Ch\u1ecdn D.<\/p>\n

V\u00ed d\u1ee5 4:<\/strong> Trong c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh sau ph\u01b0\u01a1ng tr\u00ecnh n\u00e0o kh\u00f4ng bi\u1ec3u th\u1ecb cho dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a?<\/p>\n

A. x = 5cos(\u03c0t) + 1(cm).<\/p>\n

B. x = 3tcos(100\u03c0t + \u03c0\/6)cm<\/p>\n

C. x = 2sin2<\/sup>(2\u03c0t + \u03c0\/6)cm.<\/p>\n

D. x = 3sin(5\u03c0t) + 3cos(5\u03c0t)\u00a0 (cm).<\/p>\n

Gi\u1ea3i<\/strong><\/p>\n

– A. x = 5cos\u03c0t + 1 \u2192 x \u2013 1 = 5cos(\u03c0t), n\u1ebfu ta \u0111\u1eb7t X = x \u2013 1 th\u00ec ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a v\u1eadt s\u1ebd l\u00e0 X = 5cos(\u03c0t) cm \u2192 Th\u1ecfa m\u00e3n<\/p>\n

– B. x = 3tcos(100\u03c0t + \u03c0\/6)cm \u2192 A = 3t: kh\u00f4ng th\u1ecfa m\u00e3n<\/p>\n

– C. $x=2{{\\sin }^{2}}\\left( 2\\pi t+\\frac{\\pi }{6} \\right)=1+\\cos \\left( 4\\pi t+\\frac{\\pi }{3} \\right)cm$\u2192t\u01b0\u01a1ng t\u1ef1 \u00fd A \u2192 th\u1ecfa m\u00e3n.<\/p>\n

– D. x = 3sin5\u03c0t + 3cos5\u03c0t = $3\\sqrt{2}$cos(5\u03c0t \u2013 \u03c0\/4) cm \u2192 Th\u1ecfa m\u00e3n<\/p>\n

Ch\u1ecdn B.<\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

V\u00ed d\u1ee5 1: \u00a0Dao \u0111\u1ed9ng c\u1ee7a v\u1eadt \u0111\u01b0\u1ee3c m\u00f4 t\u1ea3 b\u1eb1ng ph\u01b0\u01a1ng tr\u00ecnh x\u201d + 16x = 0. H\u00e3y x\u00e1c \u0111\u1ecbnh t\u1ea7n s\u1ed1 g\u00f3c \u03c9 c\u1ee7a v\u1eadt? A. 16 rad\/s. B. 8 rad\/s. C. 4 rad\/s. D. 10 rad\/s. Gi\u1ea3i Theo \u0111\u1ec1: x\u201d + 16x = 0 \u2192 \u03c92 = 16 \u2192 \u03c9 = 4 … \u0110\u1ecdc ti\u1ebfp<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":580,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-583","page","type-page","status-publish"],"_links":{"self":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages\/583","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/comments?post=583"}],"version-history":[{"count":3,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages\/583\/revisions"}],"predecessor-version":[{"id":593,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages\/583\/revisions\/593"}],"up":[{"embeddable":true,"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/pages\/580"}],"wp:attachment":[{"href":"https:\/\/giapsgk.com\/chuyen-de\/wp-json\/wp\/v2\/media?parent=583"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}